CODEWITHSUNDEEP
c#process.start
user2349425
user2349425

Reputation: 83

Process.start environment path

I have console application 1 which write text to file and it is in C:/app1

using (StreamWriter k = new StreamWriter("777.txt"))
    k.WriteLine("aa");

I have another console application 2, c:/app2, which start console application 1

System.Diagnostics.Process.Start("c:/app1/app1.exe");

For some reason, when I run application 2, the output 777.txt will be in folder2 instead of folder1. When I run application 1 from windows explorer, the output 777.txt will be in folder1.

I look and tried to add environment.path but it didn't solve the problem.

Upvotes: 0

Views: 274

Answers (3)

Abdessabour Mtk
Abdessabour Mtk

Reputation: 3888

you should replace your "777.txt" with AppDomain.CurrentDomain.BaseDirectory & "777.txt"

Upvotes: 1

Wagner DosAnjos
Wagner DosAnjos

Reputation: 6374

Please try the following:

        ProcessStartInfo startInfo = new ProcessStartInfo(@"c:\app1\app1.exe");
        startInfo.WorkingDirectory= @"c:\app1";

        Process.Start(startInfo);

Upvotes: 1

Andrew Barber
Andrew Barber

Reputation: 40139

Your application 1 is using a relative path, not a rooted path. That path is relative to the "current directory", not the "path" environment variable.

Process can accept a ProcessStartInfo instance which includes a property to define the current directory. You'll want to set that to the location of application 1 before starting it.

Upvotes: 1

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