CODEWITHSUNDEEP
c#argumentscmd
Igal
Igal

Reputation: 4783

Cant run application (C#) through cmd

I can't execute my application through cmd, when the application is trying to read the argument which was sent to it (text file), it fails...

When I'm trying to execute it through the IDE (vs2008), it works ok...

That's what I did in the main method:

static void Main(string[] args)
{
    int choice = 0;

    if (args.Length == 0)
       choice = 1;
    else
       choice = 2;

    switch(choice)
    {
       case 1:
          string[] text = Directory.GetFiles("allText");
          Console.WriteLine(DateTime.Now.ToString());

          foreach (string fileName in text)
          {
             string substring = fileName.Substring(8);

             ReadData_Logic rd_l = new ReadData_Logic(substring);
             rd_l.runThreadsAndDecrypt();
             rd_l.printKey(substring.Substring(0, fileName.Length - 15).Insert(0, "encryptedKey\\") + "_result.txt");
           }

           Console.WriteLine(DateTime.Now.ToString());
           break;

       case 2:
          Console.WriteLine(DateTime.Now.ToString());
          string fileName = args[0];
          Console.WriteLine(fileName); **<--- for debug, here i do see the correct file name**
          ReadData_Logic rd_l = new ReadData_Logic(fileName);
          rd_l.runThreadsAndDecrypt();
          rd_l.printKey(fileName + "_result.txt");

          Console.WriteLine(DateTime.Now.ToString());
          break;
    }
}

What's wrong with the code ? thanks

Upvotes: 0

Views: 473

Answers (2)

marc_s
marc_s

Reputation: 755371

What happens / what gets output when you add these few lines:

static void Main(string[] args)
{
    Console.WriteLine("Count of arguments: {0}", args.Length);

    int choice = 0;

    if (args.Length == 0)
       choice = 1;
    else
       choice = 2;

    Console.WriteLine("Choice now is: {0}", choice);

What do you get???

Upvotes: 0

Leniel Maccaferri
Leniel Maccaferri

Reputation: 102448

Are you passing the full path to the file as: "C:\My Documents\MyFile.txt" ?

You can only pass the file name as MyFile.txt if the file is in the same directory where you are executing the cmd/running your app.

Upvotes: 1

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