Reputation: 2639
What would be the javascript regex to determine whether the digits after the decimal point are only zero and the number of zeros after the decimal point is greater than two?
Some test cases:
8 -> false
8.0 -> false
8.00 -> false
8.000 -> true
8.0000 -> true
8.00001 -> false
Upvotes: 0
Views: 2590
Reputation: 70722
Based off your comments, if 0.000
is legal and you want to reject mutliple leading zeros along with only zeros after the decimal point being greater than two, the following should work for you.
/^(?!00)\d+\.0{3,}$/
Explanation:
^ # the beginning of the string
(?! # look ahead to see if there is not:
00 # '00'
) # end of look-ahead
\d+ # digits (0-9) (1 or more times)
\. # '.'
0{3,} # '0' (at least 3 times)
$ # before an optional \n, and the end of the string
Upvotes: 3
Reputation: 12900
Try this:
var pattern = /^\d+\.0{3,}$/; // Regex from @hwnd
function checkDigits(digits) {
var result = pattern.test(digits);
return result;
}
alert(checkDigits("5.000")); //Returns true.
Upvotes: 0
Reputation: 1509
Here is the regex which matches to a .
and then 3 or more 0s at the end of the string.
/\.0{3,}$/
Upvotes: 0