CODEWITHSUNDEEP
stringswiftinttype-conversion
Cihat Gündüz
Cihat Gündüz

Reputation: 21458

Leading zeros for Int in Swift

I'd like to convert an Int in Swift to a String with leading zeros. For example consider this code:

for myInt in 1 ... 3 {
    print("\(myInt)")
}

Currently the result of it is:

1
2
3

But I want it to be:

01
02
03

Is there a clean way of doing this within the Swift standard libraries?

Upvotes: 413

Views: 181770

Answers (12)

vacawama
vacawama

Reputation: 154513

Assuming you want a field length of 2 with leading zeros you'd do this:

import Foundation

for myInt in 1 ... 3 {
    print(String(format: "%02d", myInt))
}

output:

01
02
03

This requires import Foundation so technically it is not a part of the Swift language but a capability provided by the Foundation framework. Note that both import UIKit and import Cocoa include Foundation so it isn't necessary to import it again if you've already imported Cocoa or UIKit.

The format string can specify the format of multiple items. For instance, if you are trying to format 3 hours, 15 minutes and 7 seconds into 03:15:07 you could do it like this:

let hours = 3
let minutes = 15
let seconds = 7
print(String(format: "%02d:%02d:%02d", hours, minutes, seconds))

output:

03:15:07

Upvotes: 892

Kiran P Nair
Kiran P Nair

Reputation: 2021

For left padding add a string extension like this:

extension String {

    func padLeft(totalWidth: Int, with byString: String) -> String {
        let toPad = totalWidth - self.count
        if toPad < 1 {
            return self
        }
    
        return "".padding(toLength: toPad, withPad: byString, startingAt: 0) + self
    }
}

Using this method:

for myInt in 1...3 {
    print("\(myInt)".padLeft(totalWidth: 2, with: "0"))
}

Upvotes: 18

n a
n a

Reputation: 143

The below code generates a 3 digits string with 0 padding in front:

import Foundation

var randomInt = Int.random(in: 0..<1000)
var str = String(randomInt)
var paddingZero = String(repeating: "0", count: 3 - str.count)

print(str, str.count, paddingZero + str)

Output:

5 1 005
88 2 088
647 3 647

Upvotes: 3

mxcl
mxcl

Reputation: 26883

Using Swift 5’s fancy new extendible interpolation:

extension DefaultStringInterpolation {
    mutating func appendInterpolation(pad value: Int, toWidth width: Int, using paddingCharacter: Character = "0") {
        appendInterpolation(String(format: "%\(paddingCharacter)\(width)d", value))
    }
}

let pieCount = 3
print("I ate \(pad: pieCount, toWidth: 3, using: "0") pies")  // => `I ate 003 pies`
print("I ate \(pad: 1205, toWidth: 3, using: "0") pies")  // => `I ate 1205 pies`

Upvotes: 8

Anupam Mishra
Anupam Mishra

Reputation: 3588

Swift 4* and above you can try this also:

func leftPadding(valueString: String, toLength: Int, withPad: String = " ") -> String {
        guard toLength > valueString.count else { return valueString }
        
        let padding = String(repeating: withPad, count: toLength - valueString.count)
        return padding + valueString
    }

call the function:

leftPadding(valueString: "12", toLength: 5, withPad: "0")

Output: "00012"

Upvotes: 0

Luca Davanzo
Luca Davanzo

Reputation: 21510

Swift 5

@imanuo answers is already great, but if you are working with an application full of number, you can consider an extension like this:

extension String {

    init(withInt int: Int, leadingZeros: Int = 2) {
        self.init(format: "%0\(leadingZeros)d", int)
    }

    func leadingZeros(_ zeros: Int) -> String {
        if let int = Int(self) {
            return String(withInt: int, leadingZeros: zeros)
        }
        print("Warning: \(self) is not an Int")
        return ""
    }
    
}

In this way you can call wherever:

String(withInt: 3) 
// prints 03

String(withInt: 23, leadingZeros: 4) 
// prints 0023

"42".leadingZeros(2)
// prints 42

"54".leadingZeros(3)
// prints 054

Upvotes: 7

Imanou Petit
Imanou Petit

Reputation: 92409

With Swift 5, you may choose one of the three examples shown below in order to solve your problem.

#1. Using String's init(format:_:) initializer

Foundation provides Swift String a init(format:_:) initializer. init(format:_:) has the following declaration:

init(format: String, _ arguments: CVarArg...)

Returns a String object initialized by using a given format string as a template into which the remaining argument values are substituted.

The following Playground code shows how to create a String formatted from Int with at least two integer digits by using init(format:_:):

import Foundation

let string0 = String(format: "%02d", 0) // returns "00"
let string1 = String(format: "%02d", 1) // returns "01"
let string2 = String(format: "%02d", 10) // returns "10"
let string3 = String(format: "%02d", 100) // returns "100"

#2. Using String's init(format:arguments:) initializer

Foundation provides Swift String a init(format:arguments:) initializer. init(format:arguments:) has the following declaration:

init(format: String, arguments: [CVarArg])

Returns a String object initialized by using a given format string as a template into which the remaining argument values are substituted according to the user’s default locale.

The following Playground code shows how to create a String formatted from Int with at least two integer digits by using init(format:arguments:):

import Foundation

let string0 = String(format: "%02d", arguments: [0]) // returns "00"
let string1 = String(format: "%02d", arguments: [1]) // returns "01"
let string2 = String(format: "%02d", arguments: [10]) // returns "10"
let string3 = String(format: "%02d", arguments: [100]) // returns "100"

#3. Using NumberFormatter

Foundation provides NumberFormatter. Apple states about it:

Instances of NSNumberFormatter format the textual representation of cells that contain NSNumber objects and convert textual representations of numeric values into NSNumber objects. The representation encompasses integers, floats, and doubles; floats and doubles can be formatted to a specified decimal position.

The following Playground code shows how to create a NumberFormatter that returns String? from a Int with at least two integer digits:

import Foundation

let formatter = NumberFormatter()
formatter.minimumIntegerDigits = 2

let optionalString0 = formatter.string(from: 0) // returns Optional("00")
let optionalString1 = formatter.string(from: 1) // returns Optional("01")
let optionalString2 = formatter.string(from: 10) // returns Optional("10")
let optionalString3 = formatter.string(from: 100) // returns Optional("100")

Upvotes: 190

Vasily Bodnarchuk
Vasily Bodnarchuk

Reputation: 25294

Details

Xcode 9.0.1, swift 4.0

Solutions

Data

import Foundation

let array = [0,1,2,3,4,5,6,7,8]

Solution 1

extension Int {

    func getString(prefix: Int) -> String {
        return "\(prefix)\(self)"
    }

    func getString(prefix: String) -> String {
        return "\(prefix)\(self)"
    }
}

for item in array {
    print(item.getString(prefix: 0))
}

for item in array {
    print(item.getString(prefix: "0x"))
}

Solution 2

for item in array {
    print(String(repeatElement("0", count: 2)) + "\(item)")
}

Solution 3

extension String {

    func repeate(count: Int, string: String? = nil) -> String {

        if count > 1 {
            let repeatedString = string ?? self
            return repeatedString + repeate(count: count-1, string: repeatedString)
        }
        return self
    }
}

for item in array {
    print("0".repeate(count: 3) + "\(item)")
}

Upvotes: -1

possen
possen

Reputation: 9266

The other answers are good if you are dealing only with numbers using the format string, but this is good when you may have strings that need to be padded (although admittedly a little diffent than the question asked, seems similar in spirit). Also, be careful if the string is longer than the pad. 

   let str = "a str"
   let padAmount = max(10, str.count)
   String(repeatElement("-", count: padAmount - str.count)) + str

Output "-----a str"

Upvotes: 4

Steffen
Steffen

Reputation: 161

in Xcode 8.3.2, iOS 10.3 Thats is good to now

Sample1:

let dayMoveRaw = 5 
let dayMove = String(format: "%02d", arguments: [dayMoveRaw])
print(dayMove) // 05

Sample2:

let dayMoveRaw = 55 
let dayMove = String(format: "%02d", arguments: [dayMoveRaw])
print(dayMove) // 55

Upvotes: 3

John Cromie
John Cromie

Reputation: 201

Swift 3.0+

Left padding String extension similar to padding(toLength:withPad:startingAt:) in Foundation

extension String {
    func leftPadding(toLength: Int, withPad: String = " ") -> String {

        guard toLength > self.characters.count else { return self }

        let padding = String(repeating: withPad, count: toLength - self.characters.count)
        return padding + self
    }
}

Usage:

let s = String(123)
s.leftPadding(toLength: 8, withPad: "0") // "00000123"

Upvotes: 11

Eric Zhou
Eric Zhou

Reputation: 965

Unlike the other answers that use a formatter, you can also just add an "0" text in front of each number inside of the loop, like this: 

for myInt in 1...3 {
    println("0" + "\(myInt)")
}

But formatter is often better when you have to add suppose a designated amount of 0s for each seperate number. If you only need to add one 0, though, then it's really just your pick.

Upvotes: -12

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