CODEWITHSUNDEEP
c++templatesc++11variadic-functionsvariadic
tly
tly

Reputation: 1272

C++ variadic function: use number of parameters as template argument

I have a vector class template <unsigned int L> class Vec of variable coordinate count L.

I would like to implement the field selection feature of glsl which allows you to create new vectors by selecting like vec4 a=vec4(1,2,3,4); vec4 b=a.xyxz; //b is (1,2,1,3).

In my program i would like create something like that:

Vec<3> a={7,8,9};
Vec<4> b=a.select(0,2,2,1); //each argument is an index of the coordinate to use. 
Vec<5> c=b.select(0,1,2,3,1);

Solution:

template<typename... Args,unsigned int S=sizeof...(Args)> Vec<S> select(Args&&... args){
    Vec<S> result;
    int indices[S]={args...};
    for(int i=0;i<S;i++){
        result[i]=this->v[indices[i]]; //v is the float array that stores the values.
    }
    return result;
}

and some ridiculous examples to see if it works:

Vec<3> a={7,8,9};
Vec<9> b=a.select(0,0,1,1,0,0,1,1,2);
Vec<1> c=a.select(2);

a=[7,8,9]
b=[7,7,8,8,7,7,8,8,9]
c=[9]

Upvotes: 2

Views: 511

Answers (1)

jrok
jrok

Reputation: 55425

Like this:

template<int N>
class Vec {};

template<typename... Args>
auto foo(Args&&...) -> Vec<sizeof...(Args)>;

int main()
{
    auto v = foo(1,2,3);
    Vec<1> vv = foo(5);
}

It works with the old-style function signature syntax, too (I just prefer trailing return type in this particular case).

Upvotes: 3

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