CODEWITHSUNDEEP
haskellconduit
somebody
somebody

Reputation: 227

conduit: read-only source possible?

Suppose that I have a source keypads :: Producer IO Keypad that produces a stream of sensitive data such as one-time keypads.

Now if my library exposes keypads, an end-user might connect keypads to two sinks, let's call them good and bad, where bad requests a value and reads it, but then returns it back upstream via leftover. Later on, the good sink might consume the same keypad previously read by bad. The enduser might be oblivious to this happening, for example if good and bad are provided by external libraries.

Is there any way to design a read-only source in conduit that discards leftover data?

(I've read here that it's not possible to disable reusing leftovers, but as I'm new to conduits, maybe there's a different way to design the architecture that I'm not seeing.)

Upvotes: 3

Views: 82

Answers (1)

Michael Snoyman
Michael Snoyman

Reputation: 31315

I can think of two options:

  1. Wrap bad with a map id Conduit which will prevent leftovers from propagating. I'm thinking your code would look something like:

    keypads $$ (CL.map id =$= bad) >> good

  2. Drop down to the Pipe layer of abstraction and call injectLeftovers on bad to ensure that all leftovers are consumed there and then discarded.

I'm guessing (1) is the approach you'll want.

Upvotes: 1

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