CODEWITHSUNDEEP
pythonhtmlparsingbeautifulsouplxml
Chris Finlayson
Chris Finlayson

Reputation: 371

Python - Parse HTML class

I have tried in anger to parse the following representative HTML extract, using BeautifulSoup and lxml:

[<p class="fullDetails">
<strong>Abacus Trust Company Limited</strong>
<br/>Sixty Circular Road

            <br/>DOUGLAS

            <br/>ISLE OF MAN
            <br/>IM1 1SA
            <br/>
<br/>Tel: 01624 689600
            <br/>Fax: 01624 689601
        <br/>
<br/>
<span class="displayBlock" id="ctl00_ctl00_bodycontent_MainContent_Email">E-mail:  </span>
<a href="mailto:email@abacusion.com" id="ctl00_ctl00_bodycontent_MainContent_linkToEmail">email@abacusion.com</a>
<br/>
<span id="ctl00_ctl00_bodycontent_MainContent_Web">Web: </span>
<a href="http://www.abacusiom.com" id="ctl00_ctl00_bodycontent_MainContent_linkToSite">http://www.abacusiom.com</a>
<br/>
<br/><b>Partners(s) - ICAS members only:</b> S H Fleming, M J MacBain
        </p>]

What I want to do:

The problems I was having:

1) I could extract all text by using .findall(text=True), but there was a lot of padding in each line

2) Non-ASCII chars are sometimes returned and this would cause the csv.writer to fail.. I'm not 100% sure how to handle this correctly. (I previously just used unicodecsv.writer)

Any advice would be MUCH appreciated!

At the moment, my function just receives page data and isolates the 'p class'

def get_company_data(page_data):
    if not page_data:
        pass
    else:
        company_dets=page_data.findAll("p",{"class":"fullDetails"})
        print company_dets
        return company_dets

Upvotes: 2

Views: 795

Answers (2)

alecxe
alecxe

Reputation: 474221

Here's a complete solution:

from bs4 import BeautifulSoup, NavigableString, Tag

data = """
your html here
"""

soup = BeautifulSoup(data)
p = soup.find('p', class_='fullDetails')

company_name = p.strong.text
company_lines = []
for element in p.strong.next_siblings:
    if isinstance(element, NavigableString):
        text = element.strip()
        if text:
            company_lines.append(text)

company_email = p.find('span', text=lambda x: x.startswith('E-mail:')).find_next_sibling('a').text
company_web = p.find('span', text=lambda x: x.startswith('Web:')).find_next_sibling('a').text

print company_name
print company_lines
print com[enter link description here][1]pany_email, company_web

Prints:

Abacus Trust Company Limited
[u'Sixty Circular Road', u'DOUGLAS', u'ISLE OF MAN', u'IM1 1SA', u'Tel: 01624 689600', u'Fax: 01624 689601', u'S H Fleming, M J MacBain']
email@abacusion.com http://www.abacusiom.com

Note that to get the company lines we have to iterate over the strong tag's next siblings and get all of the text nodes. company_email and company_web are retrieved by labels, in other words, by the text of preceding to them span tags.

Upvotes: 3

sk11
sk11

Reputation: 1824

Same as you have done for p data, by using findall()

(I use lxml for the below sample codes)

To get company name:

company_name  = ''
for strg in root.findall('strong'):
    company_name = strg.text     # this will give you Abacus Trust Company Limited

To get company lines/details:

company_line_x = ''
lines = []
for b in root.findall('br'):
    if b.tail:
        addr_line = b.tail.strip()
        lines.append(addr_line) if addr_line != '' else None

company_line_x = ', '.join(lines) # this will give you Sixty Circular Road, DOUGLAS, ISLE OF MAN, IM1 1SA, Tel: 01624 689600, Fax: 01624 689601

Upvotes: 1

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