CODEWITHSUNDEEP
djangodjango-templates
Alveoli
Alveoli

Reputation: 1202

Syntax to supply a parameter to a custom template tag in {% if %} block

I have setup a custom template tag (simple_tag) (using https://stackoverflow.com/a/7716141/1369798) with a definition like this:

templatetags/polls_extras.py

def settings_value(name)

which I am able to use in my template like this:

templates/index.html

{% settings_value "ALLOWED_BOOL" %}

But this just inserts the text into my HTML output.

What is the syntax to use my template tag with parameter in an {% if %}?

I tried this but I get the error: TemplateSyntaxError at / Unused '"ALLOWED_BOOL"' at end of if expression.

templates/index.html

{% if settings_value ALLOWED_BOOL %}
You are allowed.
{% endif %}

Upvotes: 1

Views: 222

Answers (1)

bruno desthuilliers
bruno desthuilliers

Reputation: 77902

You cannot use a templatetag as a parameter to another templatetag. Your options here are either

  1. modifying your settings_value templatetag so it can inject the value in the current context, ie :

    {% settings_value ALLOWED_BOOL as allowed_bool %} {% if allowed_bool %} You are allowed. {% endif %}

Note that simple_tag won't work here, you'll either have to switch to assignement_tag (if your Django version support it) - but then you'll loose the ability to directly output a setting in the template the way you actually do - or write a full blown custom templatetag (which is not as difficult as it might seem at first).

  1. Use a custom context_processor instead like danhip suggests - but then only templates rendered using a RequestContext will access these variables.

Upvotes: 1

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