CODEWITHSUNDEEP
c#
bRaNdOn
bRaNdOn

Reputation: 1082

Create a Method with Dynamic Action parameter

Hi is there a way to create a method which accepts any kind of method? i mean any kind of parameter it has or how many parameter it has

void SampleMethod(Action<dynamic> Action)
{
}

I'm currently doing it like it but i think i doing it wrong is there a way to do that? whether it has a parameter or many or without parameter.

Am i doing wrong or i just miss something?

I have tried this code

void SampleMethod(Action Action)
{
}

but it seems that it only accepts the method without a parameter Am i doing wrong?

Upvotes: 1

Views: 3227

Answers (2)

Davut G&#252;rb&#252;z
Davut G&#252;rb&#252;z

Reputation: 5716

With Reflection,

    SampleMethod(this.GetType().GetMethod("WriteHello"), "Hello");

    public void WriteHello(string param)
    {
        Debug.WriteLine(param);
    }

    public void SampleMethod(MethodInfo mi, params object[] arguments)
    {
        mi.Invoke(this,arguments);           
    }

Upvotes: 2

Ondrej Svejdar
Ondrej Svejdar

Reputation: 22054

I think Delegate is what you're looking for.

static void A1() {
  Console.Out.WriteLine("A1");
}

static void A2(int foo) {
  Console.Out.WriteLine("A2");
}

static void SampleMethod(Delegate dlgt) {
}

Usage:

SampleMethod(new Action(A1));
SampleMethod(new Action<int>(A2));

You can invoke the method via DynamicInvoke(), however you'll have to provide exact list of arguments.

static void SampleMethod(Delegate dlgt) {
  // ok for A1, will throw an exception for A2
  dlgt.DynamicInvoke(null);
}

Upvotes: 3

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