CODEWITHSUNDEEP
javaregex
Cedy Lee
Cedy Lee

Reputation: 57

Remove characters from string regex java

Hello guys I'm starting to learn regex and I want to replace some characters from string.

this is my test case:

Example string: 

+52 924 340 2304

Expected output:

09243402304

This is what I've tried:

String number = cursor.getString(col_number).replace("\\d{2}", "");

But I can't seem to get my expected output. Any help? I would gladly appreciate your help. Thanks.

Update:

Also, I want to remove all whitespace characters from the string and I forgot to add if the string has other characters like (,),-

Upvotes: 2

Views: 4534

Answers (6)

vks
vks

Reputation: 67968

^\+\d{2}[^\d]*(\d+)[^\d]*(\d+)[^\d]*(\d+)$

You can use this and then replace with 

 0$1$2$3

See demo.

http://regex101.com/r/iX5xR2/12

This will work for all cases

Upvotes: 0

Guillaume
Guillaume

Reputation: 22822

String number = cursor.getString(col_number).replaceAll("^\\+\\d{2}", "0").replaceAll("[^\\d]", "")

Upvotes: 1

anubhava
anubhava

Reputation: 784998

Your method:

.replace("\\d{2}", "");

will fail to work because in Java String#replace doesn't take a regex. Try String#replaceAll OR String#replaceFirst

You can use:

String number = cursor.getString(col_number).replace(" ", "").replaceFirst("\\+\\d{2}", "0");

Upvotes: 1

aelor
aelor

Reputation: 11116

use this :

.replaceAll("^[^\\s]+|\\s", "")

demo here : http://regex101.com/r/uY9xB2/1

Upvotes: 1

Maroun
Maroun

Reputation: 95948

@anibhava already mentioned your problem, I want to suggest another solution, you can simply remove the white spaces and cut the string using String#substring:

number.replaceAll("\\s+", "").substring(3); //you might want to add the 0 using + operator

Upvotes: 0

PKlumpp
PKlumpp

Reputation: 5233

Why do you not split the String at the whitespaces. Then you replace the first entry with a 0, and concatenate the array parts to one String again. Done.

Upvotes: 0

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