Reputation: 23
I am facing a problem. I have some images stored in D://Images. I have to copy these images into D://Images/Modified. I tried but I did not get any output. This is my code:
define("BASE_IMAGE_PATH","D:\\");
define("IMAGE_FOLDER_NAME","2014finalfour\\");
define("IMAGE_FOLDER_NAME_MODIFIED","modified");
define("IMAGE_File_Path",BASE_IMAGE_PATH.IMAGE_FOLDER_NAME);
define("IMAGE_File_Path_Modified", BASE_IMAGE_PATH.IMAGE_FOLDER_NAME.IMAGE_FOLDER_NAME_MODIFIED);
$srcdir=constant("IMAGE_File_Path");
$destdir=constant("IMAGE_File_Path_Modified");
echo $destdir;
if (!file_exists(IMAGE_File_Path_Modified))
{
mkdir(IMAGE_File_Path_Modified, 0777, true);
}
$srcdir=opendir($srcdir);
while($readFile = readdir($srcdir))
{
if($readFile != '.' && $readFile != '..')
{
if (!file_exists($readFile))
{
if(copy($srcdir . $readFile, $destdir . $readFile))
{
echo "Copy file";
}
else
{
echo "Canot Copy file";
}
}
}
}
closedir($srcdir);
Please help me to sought out it. It says it can not copy the file. copy() expects parameter 1 to be a valid path, resource given in C:\wamp\www\marcs\testmysql.php on line 3
Upvotes: 0
Views: 68
Reputation: 1732
You could use the copy() function :
copy('foo/test.php', 'bar/test.php');
example:
<?php
$file = 'images/folder/one.jpg';
$newfile = 'Images/folder/one_thumb.jpg';
if (!copy($file, $newfile)) {
echo "failed to copy";
}
Makes a copy of the file source to dest. If the destination file already exists, it will be overwritten.
Upvotes: 1