CODEWITHSUNDEEP
xmlpowershell
David Pfeffer
David Pfeffer

Reputation: 39862

Get tag name of XML element that has a "name" property

$x = ([xml]"<sample name='notsample'/>").sample

Given the above line of code, as is, I want to find the name of the tag described by the XmlElement in $x. Typically, you would just use $x.Name, but the name attribute masks it. Instead of returning sample, $x.name returns notsample.

The only workaround I've found is:

[Xml.XmlElement].GetProperty("Name").GetValue($x)

... but this is hacky. How can I do this correctly?

Upvotes: 7

Views: 5409

Answers (2)

Mike Zboray
Mike Zboray

Reputation: 40828

You can get it by invoking the property getter method directly:

$x.get_Name()

This works in many other similar cases. For example, if a type implements IDictonary and has other properties, you may need to use this to access those properties. By default, PowerShell does a lookup into the dictionary rather than getting/setting the accessed property.

You can get PowerShell to show hidden members like these using the -Force option on Get-Member:

$x | gm -Force

Upvotes: 11

Frode F.
Frode F.

Reputation: 54911

What you are after is the LocalName property of the XmlElement class. Try:

PS> $x.LocalName
sample

Gets the local name of the current node.

Property Value

Type: System.String

The name of the current node with the prefix removed. For example, LocalName is book for the element <bk:book>.

Source: MSDN: XmlElement.LocalName

Upvotes: 4

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