Reputation: 4608
The following 406 is displayed:
The resource identified by this request is only capable of generating responses with characteristics not acceptable according to the request "accept" headers.
From what I understand the problem, I lack the conversion for displaying data in xml or json format (Maybe I am wrong on this too..) However I don't know how can I do it... Any helps are appreciated!
The codes come as followed:
import java.util.ArrayList;
import java.util.List;
import org.hibernate.HibernateException;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.Transaction;
import org.hibernate.cfg.Configuration;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.PathVariable;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.bind.annotation.ResponseBody;
@Controller
@RequestMapping("/userType")
public class UserTypeController {
private static SessionFactory factory = new Configuration().configure().buildSessionFactory();
/* Method to READ all the employees */
@RequestMapping(value = "/list.xml", method = RequestMethod.GET)
public @ResponseBody List<UserType> listUserTypes( ) {
Session session = factory.openSession();
Transaction tx = null;
try{
tx = session.beginTransaction();
List<UserType> userTypes = (List<UserType>)session.createQuery("FROM UserType").list();
return userTypes;
}catch (HibernateException e) {
if (tx!=null) tx.rollback();
e.printStackTrace();
return new ArrayList<UserType>();
}finally {
session.close();
}
}
}
The hibernate mapping class is:
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlAccessType;
@XmlRootElement(name = "UserType")
@XmlAccessorType(XmlAccessType.NONE)
public class UserType {
@XmlElement(name = "UserTypeID")
private int id;
@XmlElement(name = "UserTypeName")
private String name;
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
The spring configuration includes:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc.xsd">
<context:component-scan base-package="com.pretech" />
<mvc:annotation-driven />
</beans>
and the web.xml is:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
<display-name>SpringRestFulExample</display-name>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
</web-app>
With the above app, I am calling the following urls and they all return the same 406:
http://localhost:8080/SpringRestFulExample/userType/list.xml
http://localhost:8080/SpringRestFulExample/userType/list.json
http://localhost:8080/SpringRestFulExample/userType/list
EDIT:
I think actually the issue is about browser unable to accept List as input; however this should also be serialized into either xml or json, how can I do it?
Upvotes: 0
Views: 463
Reputation: 36
You need to serialize your response using something like Jackson or GSON (for json) and then add an @Produces annotation to set the content-type headers in the response. Jersey and Jax-RS are also nice.
Upvotes: 1