CODEWITHSUNDEEP
c#xmlc#-4.0rss
David TG
David TG

Reputation: 77

XML to string (C#)

I have a XML loaded from a URL like this:

WebClient client = new WebClient();
client.Encoding = Encoding.UTF8;

try
{
    string reply = client.DownloadString("http://Example.com/somefile.xml");
    label1.Text = reply;
}
catch
{
    label1.Text = "FAILED";

}

That XML belongs to a RSS Feed. I want that label1.Text shows just the titles of that XML. How can I achieve that?

Example of label1.Text 

This is my first title    -    This is my 2nd title    -    And this is my last title

Upvotes: 1

Views: 149

Answers (3)

Marc-Olivier Méthé
Marc-Olivier Méthé

Reputation: 26

You can load your XML into an XmlDocument and then use XPath to Get the value of each node you're targeting.

       XmlDocument doc = new XmlDocument();
       doc.LoadXml(reply);
       XmlNodeList nodes = doc.SelectNodes("//NodeToSelect");

       foreach (XmlNode node in nodes)
       {
           //If the value you want is the content of the node
           label1.Text = node.InnerText; 
           //If the value you want is an attribute of the node
           label1.Text = node.Attributes["AttibuteName"].Value; 
       }

If you are not familiar with XPath you can always check here : http://www.w3schools.com/xpath/xpath_syntax.asp

Upvotes: 1

reckface
reckface

Reputation: 5858

var xml= XElement.Parse(reply);
label1.Text = string.Join(Environment.NewLine, xml
.Descendants()
.Where (x => !string.IsNullOrEmpty(x.Value))
.Select(x=> string.Format("{0}: {1}", x.Name, x.Value))
.ToArray());

Upvotes: 1

NonStatic
NonStatic

Reputation: 1081

You probably need to parse the RSS XML manually to get the title. Here is some sample code for your reference:

private static List<FeedsItem> ParseFeeds(string feedsXml)
{
    XDocument xDoc = XDocument.Parse(feedsXml);
    XNamespace xmlns = "http://www.w3.org/2005/Atom";

    var items = from entry in xDoc.Descendants(xmlns + "entry")
                select new FeedsItem
                {
                    Id = (string)entry.Element(xmlns + "id").Value,
                    Title = (string)entry.Element(xmlns + "title").Value,
                    AlternateLink = (string)entry.Descendants(xmlns + "link").Where(link => link.Attribute("rel").Value == "alternate").First().Attribute("href").Value
                };

    Console.WriteLine("Count = {0}", items.Count());
    foreach(var i in items)
    {
        Console.WriteLine(i);
    }

    return null;
}

Upvotes: 0

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