CODEWITHSUNDEEP
pythondjangodjango-views
Hulk
Hulk

Reputation: 34200

HttpResponseRedirect question

Cant we send a dictionary variable when using HttpResponseRedirect

        render_to_response('edited/display.html',context_instance=RequestContext(request,{'newlist': newlist}))

    //How can the dictionary and the request sent back again

    //sumthing like this

    return HttpResponseRedirect('edited/display.html',context_instance=RequestContext(request,{'newlist': newlist}))

Upvotes: 2

Views: 4597

Answers (4)

asdf_enel_hak
asdf_enel_hak

Reputation: 7650

So let me add another answer additional to existing ones:

my_url = reverse("my_app.views.my_path") + "?action_result=124"
return HttpResponseRedirect(my_url)

reverse function is: from django.core.urlresolvers import reverse

Upvotes: 2

Anurag Uniyal
Anurag Uniyal

Reputation: 88845

Response redirect as name suggests, redirects the user's browser to new URL, so it doesn't make any sense to pass anything else except the new location in HttpResponseRedirect

If you want to pass some data, so that in the view of new location url you can check for that data, pass it as url arguments e.g.

return HttpResponseRedirect('edited/display.html?msg=I was redirected')

Upvotes: 4

lprsd
lprsd

Reputation: 87205

What you are really looking for, I think is the redirect function introduced in 1.1

You can instead use, for your case,

redirect(view_name,view_parameter)

For that, it may be necessary to modify your view first, to take the new_list parameter, or pass to it, the slug or the id, it takes.

Upvotes: 0

Ignacio Vazquez-Abrams
Ignacio Vazquez-Abrams

Reputation: 799350

From the documentation:

The constructor takes a single argument -- the path to redirect to. This can be a fully qualified URL (e.g. 'http://www.yahoo.com/search/') or an absolute URL with no domain (e.g. '/search/').

Upvotes: 0

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