CODEWITHSUNDEEP
iosxcodeswift
bhzag
bhzag

Reputation: 2980

GM release of Xcode 6 compile

I just downloaded the GM release of Xcode 6 and it won't compile with this error:

Command /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/swiftc failed with exit code 1

Any ideas on how to fix this?

Upvotes: 28

Views: 27725

Answers (21)

Maxwell
Maxwell

Reputation: 6822

This error can happen for numerous reasons, so this is meant to be a debugging hint. You may want to try using xcodebuild in the command line. It will give you details as to what files are the culprits.

To do this, open Terminal and go to your project folder. Once there, type in 

xcodebuild -project YourProject.xcodeproj -scheme YourScheme

or if you're working in a workspace

xcodebuild -workspace YourProject.xcworkspace -scheme YourScheme

You may see A LOT of messages pop up, but at the very end of the output you should see the specific files that are causing the crash. Back in XCode, go into those files and start playing with some of the Swift syntax to see what's going on. In my case, it had to do with the setAttributeString function, but I've seen other people have issues with ! and ?.

Hopefully that will get you headed in the right direction.

Upvotes: 70

Ron Myschuk
Ron Myschuk

Reputation: 6061

I was also getting this error. I ran the the command in Terminal as suggested by @Maxwell and found out the error was in my GameViewController.swift file. A little digging around and found that it didn't like some auto-generated code or the code conflicted with a setting in Xcode somewhere

override func supportedInterfaceOrientations() -> UIInterfaceOrientationMask {

    if UIDevice.currentDevice().userInterfaceIdiom == .Phone {
        return .AllButUpsideDown
    } else {
        return .All
    }
}

As soon as I removed this block the error went away.

Upvotes: 0

AaoIi
AaoIi

Reputation: 8396

In my case Xcode gave the error because of the following line : 

if UI_USER_INTERFACE_IDIOM() ==  UIUserInterfaceIdiom.Phone {


}else {

}

And to fix the error I've defined this :

enum UIUserInterfaceIdiom : Int {
    case Unspecified
    case Phone // iPhone and iPod touch style UI
    case Pad // iPad style UI
}

And then i used it like :

 if UIDevice.currentDevice().userInterfaceIdiom == .Phone {

}

Good luck !

Upvotes: 0

BillChan
BillChan

Reputation: 85

Encounter this error when compiling this Swift 2.0 syntax in Xcode 6.4:

print(string, appendNewline: true);

Back to Xcode 7 and the error is gone.

Upvotes: 0

Akhlaq Rao
Akhlaq Rao

Reputation: 29

Maxwell's solution gives you the closest hint.

Upvotes: 0

Julian
Julian

Reputation: 9337

I see many reasons. My answer is not a generic solution but just adding yet another case that provide to that error. In my case it was setting a button's title like this:

button!.setTitleColor(.whiteColor(), forState: UIControlState.Normal)

instead of this:

button!.setTitleColor(UIColor.whiteColor(), forState: UIControlState.Normal)

Upvotes: 2

TPot
TPot

Reputation: 340

A lot of people have this issue (me included) due to the optimisation on the compiler. I don't consider turning off the optimisation a correct resolution - I want my code optimised to run as quick as it can.

re-running xcodebuild manually didn't do any good as it ran it without the optimisations as well.

However - the error screen gave me the swiftc command that was failing:

/Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/swiftc -target arm64-apple-ios8.0 -incremental -module-name SpaceCats -O -sdk /Applic...

The -O there is the optimise flag.

I re-ran this whole command in the projects directory (as per xcodebuild recommendation above) and amongst all the details I found the error below:

{
"kind": "finished",
"name": "compile",
"pid": 10682,
"output": "Bitcast requires both operands to be pointer or neither\n  %228 = bitcast i8* %227 to %VSs20UnsafeMutablePointer, !dbg !1322\nBitcast requires both operands to be pointer or neither\n  %324 = bitcast i8* %323 to %VSs20UnsafeMutablePointer, !dbg !1322\nBitcast requires both operands to be pointer or neither\n  %411 = bitcast i8* %410 to %VSs20UnsafeMutablePointer, !dbg !1322\nBitcast requires both operands to be pointer or neither\n  %498 = bitcast i8* %497 to %VSs20UnsafeMutablePointer, !dbg !1322\nLLVM ERROR: Broken function found, compilation aborted!\n",
"exit-status": 1
}

If you want it to go to a file instead of the screen, add " 2>filename" to the end.

I then had to find the pid (10682) in the file to see what it was compiling. I ran the command for that pid manually and it gave me the error for the specific file. Then it comes down to fixing the code.

Upvotes: 2

evanchin
evanchin

Reputation: 2048

If you are using some API which should be used in early iOS version, you may get build failure. For example: If you are using UI_USER_INTERFACE_IDIOM() instead of UIDevice.currentDevice().userInterfaceIdiom to identify the device type, you will get this build error with no hint.

Upvotes: 2

Vladimir Linkevich
Vladimir Linkevich

Reputation: 61

In my case this error was caused by the incorrect (UTF8) .swift file encoding; Solved by copy-pasting the file's contents into a new file.

Upvotes: 1

Wstunes
Wstunes

Reputation: 196

change 

func tableView(tableView: UITableView!, cellForRowAtIndexPath indexPath: NSIndexPath!) -> UITableViewCell!

TO

func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell

and do the same to others like this

Upvotes: 0

Raj
Raj

Reputation: 1091

By following @maxvel's suggestion, I got to know that max() and min() functions failed to compile in the release mode. I replaced it with my own functions like below.

//Swift compiler seems to failing to compile default min and max functions in release 
//mode hence writing my own
//
func maximum<T: Comparable> (one: T, other: T) -> T {
    if one > other {
        return one
    }
    else {
        return other
    }
}

func minimum<T: Comparable> (one: T, other: T) -> T {
    if one < other {
        return one
    }
    else {
        return other
    }
}

Upvotes: 0

Max Reshetey
Max Reshetey

Reputation: 46

To add my case here. I got the described error whenever I mark the closure with [unowned self], but never reference the self in the closure itself.

For example: 

        request.startWithSuccess({ [unowned self] (req: CBRequest!, object: AnyObject!) -> Void in

            if let result = object["result"] as? [NSObject: AnyObject]
            {
                popup.type = result["email"] == nil ? AuthPopupType.Signup : AuthPopupType.Login
            }
            else
            {
                println("WARNING: Malformed response for kCBCheckUniquenesPath request.")
            }

            }, failure: { (req: CBRequest!, err: NSError!) -> Void in

                println("ERROR: Failure response for kCBCheckUniquenesPath request.")
        })

Upvotes: 0

MLQ
MLQ

Reputation: 13511

Just to put this out there: I get this error whenever I put [unowned self] in a block within a block, like this:

lazy var someVar: SomeType = {
    self.successBlock = {[unowned self] in
        // ...
    }
}()

The solution is to put the [unowned self] only at the topmost-level block. It seems an unowned reference to self is handled automatically for blocks within blocks.

Of course, I was only able to find this error by first finding out the troublesome file via @Maxwell's answer: https://stackoverflow.com/a/26848000/855680

Upvotes: 0

Evgenii
Evgenii

Reputation: 37339

I have the following code showing build error in Release.

if myValue > 5 { myValue = 5.0 }
if myValue < 0 { myValue = 0 }

Adding else between if statements fixed the issue:

if myValue > 5 { myValue = 5.0 }
else
if myValue < 0 { myValue = 0 }

Demo: https://github.com/exchangegroup/build-error-demo

Xcode Version 6.1 (6A1052d). Builds alright in debug. Submitted ticket to Apple Bug Reporter.

Upvotes: 0

tounaobun
tounaobun

Reputation: 14857

I think it occured for many reasons, what I have encountered is this situation,hope it could help you.

dispatch_async(dispatch_get_global_queue( DISPATCH_QUEUE_PRIORITY_DEFAULT, 0) ){ [weak self] in

        // ...
        dispatch_async(dispatch_get_main_queue()) { [weak self] in

            // ...
            return

        }
    }

In the upper code,just delete "[weak self]" called capture list will remove the compiler error. It works for me.

dispatch_async(dispatch_get_global_queue( DISPATCH_QUEUE_PRIORITY_DEFAULT, 0) ){ [weak self] in

        // ...
        dispatch_async(dispatch_get_main_queue()) {

            // ...
            return

        }
    }

xCode version is 6.1.1

Upvotes: 3

Harris Fu
Harris Fu

Reputation: 21

Go to the folder: Users/user/Library/Developer/Xcode/DerivedData

and clear all file,

then then clean and analyze,

It`s work to me.

Upvotes: 0

Weles
Weles

Reputation: 1275

In my case i changed 3 places:

Target > Build Settings > Swift Compiler >

  • Optimization Level.
    • Debug: None [-Onone]
    • Distribution: Fastest [-O]
    • Release: Fastest [-O]

When i changed just Debug, i have errors like "Source Kit crashed...." This combination of parameters, works very good for me!

Upvotes: 2

tuoxie007
tuoxie007

Reputation: 1236

May be the same issue Swift compile error in XCode 6 GM

I had the same problem, then I use git checkout old versions to find which commit cause the problem, and try to find the key problem code. My key problem code is something like this

func afunc() {
    class AClass() {
    }
    let ac = AClass()
    //....
}

Other code could make the same problem, occur in Swift Optimization, and swift compiler doesn't tell you the exact location. This must be a bug by Apple.

Upvotes: 2

Byron Coetsee
Byron Coetsee

Reputation: 3593

I had to change my "Optimization Level" to None[-0none]

Target > Build Settings > Swift Compiler > Optimization Level.

Upvotes: 10

Michał Kreft
Michał Kreft

Reputation: 558

My case was a little bit different and it involves enums and optionals. For the simplicity lets define

enum Animal {
    case Dog
    case Cat
}

func exampleAction(animal: Animal) {}

exampleAction(.Cat)

It will run OK. However as soon as I made the argument optional the error started to appear. So this code won't work:

func exampleAction(animal: Animal?) {}

exampleAction(.Cat)

To make it work I had to add explicit enum name in the method call. So the following code worked again:

exampleAction(Animal.Cat)

Upvotes: 7

Tinyfool
Tinyfool

Reputation: 1480

I think the real problem is there are too many errors, so the compile tell you only a confused error code.

But you can always open the every source code file, in there you can find the detail error information and correct advice.

Good luck!

Upvotes: -2

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