user3264438
user3264438

Reputation: 33

How to save log output in a file in linux

I need to create an accessible log file in our linux server. A java program is used to create a log.

In my console

Sep 11, 2014 3:03:05 PM com.gsis.bom.Log appLog
SEVERE: test 1
Sep 11, 2014 3:03:06 PM com.gsis.bom.Log appLog
INFO: test 2
Sep 11, 2014 3:03:06 PM com.gsis.bom.Log appLog
INFO: test 3

But this messages should be saved in a file in linux. For e.g. /home/logs How can I do it?

THANK YOU

EDIT

LogManager lm = LogManager.getLogManager();
          Logger logger;
          FileHandler fh = new FileHandler("log_test.txt");

          logger = Logger.getLogger("LoggingExample1");

          lm.addLogger(logger);
          logger.setLevel(Level.INFO);
          fh.setFormatter(new XMLFormatter());

          logger.addHandler(fh);
          logger.log(Level.SEVERE, "test 1");
          logger.log(Level.INFO, "test 2");
          logger.log(Level.INFO, "test 3");
          fh.close();

This is the code that I am using. Ok I can see it in my console. But I need the messages to be saved in a file. For example at /home/logs/log.txt in our linux server

Upvotes: 0

Views: 2462

Answers (2)

Paul Vargas
Paul Vargas

Reputation: 42020

Seems that you are using . In that case, you can add an appender programmatically as in the following example.

// the maximum number of bytes to write to any one file
int limit = 5 * 1024 * 1024; 

// the number of files to use
int count = 10;              

Handler handler = new FileHandler("/home/logs/log_test.txt", limit, count);
Logger.getLogger("").addHandler(handler);

You may want to see Where does java.util.logging.Logger store their log, Java logging opening "too many" logfiles and Java Logging API generating empty log files

Upvotes: 0

shrishinde
shrishinde

Reputation: 3405

You can use class something like below,

import org.apache.log4j.Logger;

public class CreateLog{

    static Logger logEntry = Logger.getLogger(
                  CreateLog.class.getName());

    public void testLog(){
        logEntry.info("some information message");
        logEntry .error("some error message");
    }
}

Upvotes: 2

Related Questions