Reputation: 419
Below is an example how can I use a simple MySQL query that I can do from step 1 ->step 4
step 1: original table
object prob
dog
dog
cat
cat
book
book
step 2: count the object
dog 2
cat 2
book 2
step 3: calculate the probability
dog 2/(2+2+2)
cat 2/(2+2+2)
book 2/(2+2+2)
step 4: return the probability value to original
Object prob
dog 2/6
dog 2/6
cat 2/6
cat 2/6
book 2/6
book 2/6
Upvotes: 0
Views: 481
Reputation: 509
What exactly are you asking?
You want to know how to Count each item and insert the probability of each?
Update:
This piece of code will do what you are asking. Just replace #temp with your own table.
DECLARE @object nvarchar(max)
DECLARE object_cursor CURSOR FOR
SELECT object
FROM #temp
OPEN object_cursor
FETCH NEXT FROM object_cursor
INTO @object
WHILE @@FETCH_STATUS = 0
BEGIN
UPDATE #temp
SET prob = (
SELECT
COUNT(object)
FROM #temp
WHERE object = @object
)
FETCH NEXT FROM object_cursor
INTO @object
END
CLOSE object_cursor
DEALLOCATE object_cursor
UPDATE #temp
SET prob = prob / (select SUM(prob) from #temp)
Upvotes: 1