Reputation: 9
This is the code which is not working according to my requirement
<head>
<script type="text/javascript">
function test(){
if(document.form.choice.value='pc'){
window.open('pc.php','_self');
return true;
}
else if(document.form.choice.value='ps2'){
window.open('ps2.php','_self');
return true;
}
else if(document.form.choice.value='ps3'){
window.open('ps3.php','_self');
return true;
}
else if(document.form.choice.value='psp'){
window.open('psp.php','_self');
return true;
}
}
</script>
</head>
<body>
Games<br /><br />
<form name="form">ALL
<input type="radio" onClick="test()" name="choice" value="pc">PC
<input type="radio" onClick="test()" name="choice" value="ps2">PS2
<input type="radio" onClick="test()" name="choice" value="ps3">PS3
<input type="radio" onClick="test()" name="choice" value="psp">PSP
</form>
</body>
Also i want to know that how to display the field automatically just by selecting the selected field in Drop down list without 'submit'
<select name="genre">
<option value="">--Select Genre and Click Go--</option>
<option value="All">All</option>
<option value="Action / Mission">Action / Mission</option>
<option value="Arcade">Arcade</option>
<option value="Racing">Racing</option>
<option value="Sports">Sports</option>
<option value="Kids">Kids</option>
<option value="Strategy">Strategy</option>
<option value="Adventure">Adventure</option>
</select>
Upvotes: 0
Views: 15292
Reputation: 62
Try this...
EDITED:
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"> </script>
<script type="text/javascript">
function idForm(){
var selectvalue = $('input[name=choice]:checked', '#idForm').val();
if(selectvalue == "pc"){
window.open('http://www.google.com','_self');
return true;
}
else if(selectvalue == "ps2"){
window.open('http://www.google.com','_self');
return true;
}else if(selectvalue == 'ps3'){
window.open('http://www.google.com','_self');
return true;
}else if(selectvalue == 'psp'){
window.open('http://www.google.com','_self');
return true;
}
return false;
};
</script>
</head>
<body>
Games<br /><br />
<form id="idForm">ALL
<input type="radio" onclick="idForm()" name="choice" value="pc"/>PC
<input type="radio" onclick="idForm()" name="choice" value="ps2"/>PS2
<input type="radio" onclick="idForm()" name="choice" value="ps3"/>PS3
<input type="radio" onclick="idForm()" name="choice" value="psp"/>PSP
</form>
</body>
Jsfiddle link
Upvotes: 1
Reputation: 5858
You can get the value of the option by adding onchange
event in the <select>
tag.
<select name="genre" onchange="selectOption()">
<option value="">--Select Genre and Click Go--</option>
<option value="All">All</option>
<option value="Action / Mission">Action / Mission</option>
<option value="Arcade">Arcade</option>
<option value="Racing">Racing</option>
<option value="Sports">Sports</option>
<option value="Kids">Kids</option>
<option value="Strategy">Strategy</option>
<option value="Adventure">Adventure</option>
</select>
In your script add this
function selectOption(){
//each option value
var option=document.form.genre.value;
alert(option);
}
For redirecting you can use window.location
in your test()
method
use this window.location=yourpage.php
instead of this window.open('pc.php','_self')
Upvotes: 0