CODEWITHSUNDEEP
c++linked-list
Lion King
Lion King

Reputation: 33813

cannot convert 'listNode**' to 'listNode*' in assignment

I have an error when create a simple linked list.
The error message is cannot convert 'listNode**' to 'listNode*' in assignment.

The code:

struct listNode {
    const char *data;
    listNode *link;
};


int main(){
    listNode *node = new listNode;
    node->data = "Adley";
    node->link = NULL;

    listNode *node2 = new listNode;
    node2->data = "Bert";
    node2->link = NULL;

    listNode *node3 = new listNode;
    node3->data = "Colin";
    node3->link = NULL;

    node->link = &node2;
    node2->link = &node3;

    for(listNode *i = &node; i != NULL; i = i->link){
        std::cout << i->data << std::endl;
    }

    return 0;
}

I know that this question is easy to solve it, but I'm sorry my brain is confused now.

Upvotes: 0

Views: 3125

Answers (2)

Dahley
Dahley

Reputation: 71

for(listNode *i = node; i != NULL; i = i->link){
    std::cout << i->data << std::endl;
}

you must use *i=node NOT *i=&node in the init-expression of the for

the type of i : listNode*
the type of node : listNode*
but the type of &node : listNode**

Upvotes: 0

fredoverflow
fredoverflow

Reputation: 263260

Change:

node->link = &node2;
node2->link = &node3;

To:

node->link = node2;
node2->link = node3;

Remove the ampersands(&). node2 and node3 are already pointers. No need to point to pointers :)

Upvotes: 1

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