CODEWITHSUNDEEP
pythonregex
James Garner
James Garner

Reputation: 15

Regular Expressions, using search in python

I want to decode a some hex in python.

In part of the string \xcd\xed\xb0\xb2

    text = re.search(r'(\\x\w{2}){4}', rtf)

    unicodeText = text.decode('gb2312')

Error: '_sre.SRE_Match' object has no attribute 'decode'

Hope someone can help, Thanks

Upvotes: 0

Views: 185

Answers (1)

falsetru
falsetru

Reputation: 368894

re.search returns a Match object, not a matched string.

Use group method to get the matched string.

>>> rtf = r'\xcd\xed\xb0\xb2'
>>> matched = re.search(r'(\\x\w{2}){4}', rtf)
>>> text = matched.group()
>>> text.decode('string-escape').decode('gb2312')
u'\u665a\u5b89'

# In Python 3.x
# >>> text.encode().decode('unicode-escape').encode('latin1').decode('gb2312')
# '晚安'

BTW, you don't need to use regular expression, what you want is convert \xOO:

Python 2.x:

>>> rtf = r'\xcd\xed\xb0\xb2'
>>> rtf.decode('string-escape').decode('gb2312')
u'\u665a\u5b89'
>>> print rtf.decode('string-escape').decode('gb2312')
晚安

Python 3.x:

>>> rtf = r'\xcd\xed\xb0\xb2'
>>> rtf.encode().decode('unicode-escape').encode('latin1').decode('gb2312')
'晚安'

Upvotes: 1

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