Reputation: 170
I am trying to make a 2d array using a pointer of pointers and have hit a wall. My program crashes as soon as I try to scan in values to store in 1st matrix (line 38). I want to store a value in the address of m1[i][j]
and m1[i][j] == *(*m1+i)+j
correct?
I have supplied the code below (up until the point of crashing). What is going on here? Why is it crashing when scanning in input for matrix 1?
#include <stdio.h>
#include <stdlib.h>
#include<conio.h>
int main() {
//Initializing variables
int i= 0, j = 0, m = 0, n = 0, p = 0, q = 0;
double **m1, **m2, **mr;
//Prompt user to enter dimensions of first matrix.
printf("Enter number of rows and columns of 1st matrix:");
scanf("%d %d",&m,&n); //Scanning user input
//Prompt user to enter dimension of second matrix.
printf("Enter number of rows and columns of 2nd matrix:");
scanf("%d %d",&p,&q); //Scanning input
//Check if cols (matrix 1) and rows (matrix 2) are equal
if(n!=p)
printf("Not possible");
//If M1 cols == M2 rows allocate memory for matrices
else {
m1 = malloc(sizeof(double *) * m);
for( i=0; i < m; i++)
m1[i] = calloc(n, sizeof(double));
m2 = malloc(sizeof(double *) * p);
for( i=0; i < p; i++)
m2[i] = calloc(q, sizeof(double));
mr = malloc(sizeof(double *) * m);
for( i=0; i < m; i++)
mr[i] = calloc(q, sizeof(double));
//Prompt user to enter values for matrix 1
printf("Enter 1st matrix values:");
//For loop for number of rows
for(i=0;i<m;i++) {
//For loop for number of cols
for(j=0;j<n;j++) {
scanf("%lf\t", *(*(m1+i)+j)); //Scanning input
}
}
//Prompt user to enter values for matrix 2
printf("Enter 2nd matrix values:\n");
for(i=0;i<p;i++) {
for(j=0;j<q;j++) {
scanf("%lf", &(*(m2+i)+j)); //Scanning input
}
}
Upvotes: 0
Views: 1225
Reputation: 206747
This line is not right:
scanf("%lf\t", *(*(m1+i)+j)); //Scanning input
The type of *(*(m1+i)+j)
is double
, not double*
, which is what you need for scanf
.
You need to use
scanf("%lf\t", *(m1+i)+j); //Scanning input
or, a simpler form:
scanf("%lf\t", &m1[i][j]); //Scanning input
You have similar errors in the other loops.
Upvotes: 1