CODEWITHSUNDEEP
javamodulusdivide
user3558676
user3558676

Reputation: 17

Divide 2 numbers and see if the first one divides the second number evenly

I need to create a program that reads 2 integers from the keyboard and prints a message saying whether the first number divides the second evenly.

I know I have to use either / or %, but it's not working.

int y, x,z;

System.out.print("Enter first number: ");
x= keyboard.nextInt();
System.out.print("Enter second number: ");
y= keyboard.nextInt();
z=y/x;
if (z%2==0){
    System.out.println("Divides evenly");
} else {
    System.out.println("Does not divide evenly");
}

I have to divide y by x. So, for example, x= 25 y=100, it should come out even. Then x=35 y=100 not even.

I've tried

 z==0

 z%y==0

Not working.

Upvotes: 1

Views: 7134

Answers (2)

Tyler
Tyler

Reputation: 18177

You're close, you don't need the extra integer division.

Integer division ( % ) gives you the remainder. So when you do z=y%x;, all you need to do in your if statement is check that z is equal to 0 (meaning that the first number evenly decided the second number).

int y, x,z;

System.out.print("Enter first number: ");
x= keyboard.nextInt();
System.out.print("Enter second number: ");
y= keyboard.nextInt();
z=y%x;
if (z==0){  //Changed this liine
    System.out.println("Divides evenly");
} else {
    System.out.println("Does not divide evenly");
}

Upvotes: 3

rock
rock

Reputation: 36

    int x,y;

    System.out.print("Enter first number: ");
    x= keyboard.nextInt();
    System.out.print("Enter second number: ");
    y= keyboard.nextInt();

    if (x%y==0){
    System.out.println("Divides evenly");
    } else {
    System.out.println("Does not divide evenly");
    }

Upvotes: 1

Related Questions