Kamousagi
Kamousagi

Reputation: 11

laravel 4 rapyd model

I am new to laravel, use the complement Rapyd Laravel, sent me the following problem:

[2014-09-16 02:26:01] production.ERROR: exception 'ErrorException' with message 'Use of undefined constant Autor - assumed 'Autor'' in C:\wamp\www\prueba3\app\controllers\AutorController.php:11
Stack trace:
#0 C:\wamp\www\prueba3\app\controllers\AutorController.php(11): Illuminate\Exception\Handler->handleError(8, 'Use of undefine...', 'C:\wamp\www\pru...', 11, Array)

I hope you can help me, below image link

https://imagizer.imageshack.us/v2/1448x815q90/674/1YVKfP.png

When this use, works well:

$set = DataSet::source("Bib_Autor");

When this use, does not work

$set = DataSet::source(Autor);

Im new... ty

Upvotes: 0

Views: 120

Answers (2)

Felice Ostuni
Felice Ostuni

Reputation: 1080

You should instantiate a model or use the Eloquent query builder

$set = DataSet::source(new Autor);

$set = DataSet::source(DB::table("autors"));

as explained here: https://github.com/zofe/rapyd-laravel/wiki/DataSet

Upvotes: 0

Laurence
Laurence

Reputation: 60068

You probably meant to change this:

$set = DataSet::source(Autor);

to this

$set = DataSet::source("Autor");

Upvotes: 1

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