dontoo
dontoo

Reputation: 843

How does MatchEvaluator in Regex.Replace work?

This is the input string 23x * y34x2. I want to insert " * " (star surrounded by whitespaces) after every number followed by letter, and after every letter followed by number. So my output string would look like this: 23 * x * y * 34 * x * 2.

This is the regex that does the job: @"\d(?=[a-z])|[a-z](?=\d)". This is the function that I wrote that inserts the " * ".

Regex reg = new Regex(@"\d(?=[a-z])|[a-z](?=\d)");   
MatchCollection matchC;
matchC = reg.Matches(input);
int ii = 1;
foreach (Match element in matchC)//foreach match I will find the index of that match
{
    input = input.Insert(element.Index + ii, " * ");//since I' am inserting " * " ( 3 characters )
    ii += 3;                                        //I must increment index by 3
}
return input; //return modified input

My question how to do same job using .net MatchEvaluator? I am new to regex and don't understand good replacing with MatchEvaluator. This is the code that I tried to wrote:

{
    Regex reg = new Regex(@"\d(?=[a-z])|[a-z](?=\d)");
    MatchEvaluator matchEval = new MatchEvaluator(ReplaceStar);
    input = reg.Replace(input, matchEval);
    return input;
}
public string ReplaceStar( Match match )
{
    //return What??
}

Upvotes: 62

Views: 39812

Answers (2)

Max Kleiner
Max Kleiner

Reputation: 1612

In Delphi or maXbox you have the same possibility:

  writeln('match eval3');
  with TregEx.create1('\d(?=[a-z])|[a-z](?=\d)') do begin
    writeln(Replace1('23x * y34x2', @matcheval)); 
  free; end;  

and matcheval is a callback or anonymous as

  function matcheval(const Match: TMatch): string;
  begin
    result:= match.Value + ' * ';
  end;

Behind the scene works also a core regex as $ function or called backreference (is called 4 times) that does the same!:

  writeln(regexReplaceall('23x * y34x2','\d(?=[a-z])|[a-z](?=\d)', '$+ * ', []));

23 * x * y * 34 * x * 2

Upvotes: 1

Mark Byers
Mark Byers

Reputation: 838116

A MatchEvaluator is a delegate that takes a Match object and returns a string that should be replaced instead of the match. You can also refer to groups from the match. You can rewrite your code as follows:

string input = "23x * y34x2";
Regex reg = new Regex(@"\d(?=[a-z])|[a-z](?=\d)");
string result = reg.Replace(input, delegate(Match m) {
    return m.Value + " * ";
});

To give an example of how this works, the first time the delegate is called, Match parameter will be a match on the string "3". The delegate in this case is defined to return the match itself as a string concatenated with " * ". So the first "3" is replaced with "3 * ".

The process continues in this way, with delegate being called once for each match in the original string.

Upvotes: 89

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