Reputation: 266
I know, its simple to select all articles with at least on of tags "14 OR 16 OR 17" ... (only simple disjunction) ...
SELECT _article_id from articles_x_tags
WHERE _id_tag in (14,16,17)
GROUP BY _id_article
How to do same thing (quick way, and only one sql query) when i have to list articles with these tags "(14 OR 16) AND (17 OR 18) AND NOT(13)" ? ... (negation, conjunction, disjunction) ... Thank you for your help and ideas!
SAMPLE TABLE: articles_x_tags
╔════════════════╦════════════════════╗
║ _id_tag(int11) ║ _id_article(int11) ║
╠════════════════╬════════════════════╣
║ 14 ║ 2566 ║
║ 17 ║ 2566 ║
║ 13 ║ 2566 ║
║ 14 ║ 2567 ║
║ 17 ║ 2567 ║
║ 14 ║ 2568 ║
║ ... ║ ... milion records ║
╚════════════════╩════════════════════╝
Upvotes: 1
Views: 20
Reputation: 49069
I would use a query like this:
SELECT
id_article
FROM
articles_x_tags
WHERE
id_tag IN (14, 16, 17, 18, 13)
GROUP BY
id_article
HAVING
SUM(id_tag=14 OR id_tag=16)>0
AND SUM(id_tag=17 OR id_tag=18)>0
AND SUM(id_tag=13)=0
Upvotes: 1