CODEWITHSUNDEEP
phpmime-types
user3383418
user3383418

Reputation: 37

finfo_file returns empty string

I am trying to check the mime type of an uploaded file before I move it but I cannot get finfo_file to return anything.

$finfo = finfo_open(FILEINFO_MIME_TYPE);
$mime = finfo_file($finfo, $_FILES['imageFile']['tmp_name']);
echo $mime;
// returns NOTHING!

...so just to test in finfo_file is available and the file path is good:

echo phpversion();
// returns 5.1.28

$finfo = finfo_open(FILEINFO_MIME_TYPE);
foreach (glob("*") as $filename) {
    echo finfo_file($finfo, $filename) . ', ';
}
// returns text/plain, text/html, image/png, directory, text/x-asm, text/x-php, text/x-php, text/x-php, directory, directory

echo move_uploaded_file($_FILES['imageFile']['tmp_name'], getcwd().'/uploadsTemp/'. uniqid());
// returns 1

Can it be that somehow finfo_file cannot read the file?

Upvotes: 2

Views: 2565

Answers (3)

Svitlana Kuievda
Svitlana Kuievda

Reputation: 26

I believe, it (finfo_file) returns not just mime type, but text description of the contents of the file. Visit.this.page

Try to use this $imageinfo['mime']. Maybe it helps!

And there can be one suggestion, but I am not sure, why must you use $_FILES['imageFile']['tmp_name'] instead of $_FILES['imageFile']['name']? Is it so important to use temporary file?

Upvotes: 0

Roland Leurs
Roland Leurs

Reputation: 29

Today I had the same problem and this was caused because the uploaded file was larger than the upload_max_filesize in php.ini.

I just notice it here since I could not find this solution in other posts.

Upvotes: 2

DHeadshot
DHeadshot

Reputation: 43

This might be a stupid answer as there may be many reasons why you can't use this but...

Can you not just use $_FILES["Img"]["type"] and use the MIME types given by that?

Sorry if that doesn't answer your question.

Upvotes: -1

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