Reputation: 119
I'm looking for a way to hide a Pane for a short time (around 100ms) and then immediately show it again.
Right now I'm using a StackPane with two AnchorPanes on top, and on key press I remove the top pane. However, that doesn't seem to happen immediately and it takes way too long.
I also tried using CSS to make the top pane invisible, but that doesn't seem to do anything at all.
Here's some code of that:
pn_middle.setStyle("-fx-background-color: rgba(128, 128, 128, 0);");
try {
Thread.sleep(1000); //1 sec for testing
} catch (InterruptedException e) {
e.printStackTrace();
}
pn_middle.setStyle("-fx-background-color: rgba(128, 128, 128, 1);");
Upvotes: 1
Views: 6472
Reputation: 36722
Use a Timer
to clock the time for which you want to hide your Pane
. Try the example out, it contains a StackPane
which has a Pane, colored as PINK
and a Button
. On the click of the Button
, the Pane
is hidden for 1000ms
import java.util.Timer;
import java.util.TimerTask;
import javafx.application.Application;
import javafx.application.Platform;
import javafx.event.ActionEvent;
import javafx.event.EventHandler;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.layout.Pane;
import javafx.scene.layout.StackPane;
import javafx.stage.Stage;
public class HideAndShowPane extends Application {
@Override
public void start(Stage primaryStage) throws Exception {
StackPane stackPane = new StackPane();
Button button = new Button("Click Me to hide Pane !");
Pane pane = new Pane();
button.setOnAction(new EventHandler<ActionEvent>() {
@Override
public void handle(ActionEvent event) {
//Hide the Pane
pane.setVisible(false);
//Schedule the Visibility for 1000ms
Timer timer = new Timer();
timer.schedule(new TimerTask() {
@Override
public void run() {
//Run on UI thread
Platform.runLater(new Runnable() {
@Override
public void run() {
pane.setVisible(true);
}
});
}
}, 1000);
}
});
pane.setPrefSize(200, 200);
pane.setStyle("-fx-background-color : PINK");
stackPane.getChildren().addAll(pane, button);
Scene scene = new Scene(stackPane, 500, 500);
primaryStage.setScene(scene);
primaryStage.show();
}
public static void main(String[] args) {
launch(args);
}
}
Using Task
You can also achieve this by using Task
and Thread.sleep
ad later binding the valueProperty
of the Task with the visibleProperty
of the Pane
button.setOnAction(new EventHandler<ActionEvent>() {
@Override
public void handle(ActionEvent event) {
//Create a Task
Task<Boolean> task = new Task<Boolean>() {
@Override
protected Boolean call() throws Exception {
try {
//Invisible for 1000ms
Thread.sleep(1000);
}
catch (InterruptedException e) {
return Boolean.FALSE;
}
return Boolean.TRUE;
}
};
//Start the Task
new Thread(task).start();
//Bind the visibility with Task Value
pane.visibleProperty().bind(task.valueProperty());
}
});
Without creating any new Threads
Thanks to Tomas Mikula's answer, this can also be achieved without creating any new Thread. Using a combination of Timeline
, KeyFrames
and KeyValue
button.setOnAction(new EventHandler<ActionEvent>() {
@Override
public void handle(ActionEvent event) {
pane.setVisible(false);
Timeline timeline = new Timeline();
timeline.getKeyFrames().add(
new KeyFrame(Duration.millis(1000),
new KeyValue(pane.visibleProperty(), true)));
timeline.play();
}
});
Upvotes: 1
Reputation: 6537
If you use JavaFX 8, here is a solution using a timer from ReactFX. Unlike @ItachiUchiha's solution, it does not create any new threads.
import java.time.Duration;
import org.reactfx.util.FxTimer;
button.setOnAction(event -> {
pane.setVisible(false);
FXTimer.runLater(Duration.ofMillis(1000), () -> pane.setVisible(false));
});
Upvotes: 2