Reputation: 928
fmt.Println("a","b")
I want to print the two strings without space padding, namely "ab", but the above will print "a b".
Do I just switch to using Printf
?
fmt.Printf("%s%s\n","a","b")
Upvotes: 16
Views: 16311
Reputation: 11626
Plain old print will work if you make the last element "\n".
It will also be easier to read if you aren't used to printf style formatting.
See here on play
fmt.Println("a","b")
fmt.Print("a","b","\n")
fmt.Printf("%s%s\n","a","b")
will print:
a b
ab
ab
Upvotes: 18
Reputation: 206
the solution in my project
package main
import "fmt"
var formatMap = map[int]string{
0: "",
1: "%v",
}
func Println(v ...interface{}) {
l := len(v)
if s, isOk := formatMap[l]; !isOk {
for i := 0; i < len(v); i++ {
s += "%v"
}
formatMap[l] = s
}
s := formatMap[l] + "\n"
fmt.Printf(s, v...)
}
func main() {
Println()
Println("a", "b")
Println("a", "b")
Println("a", "b", "c", 1)
}
Upvotes: -1
Reputation: 76765
You'd have to benchmark to compare performance, but I'd rather use the following than a Printf
:
fmt.Println(strings.Join([]string{"a", "b"}, ""))
Remember to import "strings"
, and see strings.Join
documentation for an explanation.
Upvotes: -1
Reputation: 15141
As it can be found in the doc:
Println formats using the default formats for its operands and writes to standard output. Spaces are always added between operands and a newline is appended. It returns the number of bytes written and any write error encountered.
So you either need to do what you already said or you can concatenate the strings before printing:
fmt.Println("a"+"b")
Depending on your usecase you can use strings.Join(myStrings, "")
for that purpose.
Upvotes: 12
Reputation: 2654
Println relies on doPrint(args, true, true)
, where first argument is addspace
and second is addnewline
. So Prinln ith multiple arguments will always print space.
It seems there is no call of doPrint(args, false, true)
which is what you want.
Printf
may be a solution, Print
also but you should add a newline.
Upvotes: 2