Reputation: 5741
I would like to draw four circles of two colors. I'm using circle function to draw a circle. I'm facing problem with legend()
. It colors the two data with the same color.
function main
clear all
clc
circle([ 10, 0], 3, 'b')
circle([-10, 0], 3, 'b')
circle([ 10, 10], 3, 'r')
circle([-10, 10], 3, 'r')
% Nested function to draw a circle
function circle(center,radius, color)
axis([-20, 20, -20 20])
hold on;
angle = 0:0.1:2*pi;
grid on
x = center(1) + radius*cos(angle);
y = center(2) + radius*sin(angle);
plot(x,y, color, 'LineWidth', 2);
xlabel('x-axis');
ylabel('y-axis');
title('Est vs Tr')
legend('true','estimated');
end
end
The following picture shows the problem. Both colored as blue instead one of them is red.
Any suggestions?
Upvotes: 1
Views: 919
Reputation: 4311
You can make your function circle()
return the plot handles. Store the handles in a vector. In the end, you only call legend()
once, after plotting all circles. The first argument in legend are then the function handles which you want to appear in the legend. Something like this:
function main
% clear all % functions have their own workspace, this should always be empty anyway
clc
handles = NaN(1,2);
handles(1,1) = circle([ 10, 0], 3, 'b'); % handle of a blue circle
circle([-10, 0], 3, 'b')
handles(1,2) = circle([ 10, 10], 3, 'r'); % handle of a red circle
circle([-10, 10], 3, 'r')
% Nested function to draw a circle
function h = circle(center,radius, color) % now returns plot handle
axis([-20, 20, -20 20])
hold on;
angle = 0:0.1:2*pi;
grid on
x = center(1) + radius*cos(angle);
y = center(2) + radius*sin(angle);
h = plot(x,y, color, 'LineWidth', 2);
xlabel('x-axis');
ylabel('y-axis');
title('Est vs Tr')
end
% legend outside of the function
legend(handles, 'true','estimated'); % legend for a blue and a red circle handle
end
The result looks like this:
Upvotes: 3
Reputation: 21563
The thing is that you draw 4 things and only have 2 entries in the legend. As such it will pick the color of the first four things to color the legend.
Not in the opportunity to try it myself now, but I guess that the easiest 'solution' would be to draw your third circle first and then the second one.
circle([ 10, 0], 3, 'b')
circle([ 10, 10], 3, 'r')
circle([-10, 0], 3, 'b')
circle([-10, 10], 3, 'r')
Upvotes: 1