CODEWITHSUNDEEP
javaxmlsaxparser
user3373261
user3373261

Reputation: 55

Using SaxParser to get an ID

I'm currently trying to make a java file that can do an export with xml. The only thing I need to actually retrieve is the staff id's and nothing else.If my xml file looks like this: 

<? xml version= "1.0" ?>
< company>
    < staff id = "22" >
           < firstname> kate </firstname >
           < lastname> kim </lastname >
           < nickname> lolo </nickname >
           < salary> 10560</ salary >
    </ staff>
    < staff>
           < firstname> Chelsea </firstname >
           < lastname> young</ lastname >
           < nickname> cheloung </nickname >
           < salary> 200700</ salary >
    </ staff>
    < staff id = "23" >
    < firstname> Dani </firstname >
           < lastname> Heil </lastname >
           < nickname> Heily </nickname >
           < salary> 300000</ salary >
    </ staff>
 </ company>

and my java code looks like this:

package xmlfunctions;

import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;

public class saxParser {

 public static void main(String argv[]) {

 try {

 SAXParserFactory factory = SAXParserFactory.newInstance();
 SAXParser saxParser = factory.newSAXParser();

 DefaultHandler handler = new DefaultHandler() {

 boolean bfname = false;


 public void startElement(String uri, String localName,String qName, 
            Attributes attributes) throws SAXException {

      System.out.println("Start Element :" + qName);

      if (qName.equalsIgnoreCase("FIRSTNAME")) {
           bfname = true;
      }



 }

 public void endElement(String uri, String localName,
      String qName) throws SAXException {

      System.out.println("End Element :" + qName);

 }

 public void characters(char ch[], int start, int length) throws SAXException {

      if (bfname) {
           System.out.println("First Name : " + new String(ch, start, length));
           bfname = false;
      }



 }

 };

   saxParser.parse("KatesFile.xml", handler);

 } catch (Exception e) {
   e.printStackTrace();
 }

  }

 }

How can I change it to get it to display the staff id only? That is all I really want not the other tags. Can anyone help please? I'm very unsure as to how to get the id's on their own.

Upvotes: 1

Views: 291

Answers (1)

Junior Dussouillez
Junior Dussouillez

Reputation: 2397

You can get the value of id in startElement(), using the parameter attributes.

public void startElement(String uri, String localName,String qName,Attributes attributes) throws SAXException {
    if (qName.equals("staff")) {
        System.out.println(attributes.getValue("id"));
    }
}

If there is no id in <staff>, the value is null.

Upvotes: 1

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