Reputation: 3461
somebody was nice enough to give me a solution from my first problem (using a function on pairwise "all vs all" combinations of a collection of matrices):
library(vegan)
#by Akrun
A <- matrix(sample.int(100, size = 50*50, replace = TRUE), nrow = 50, ncol = 50)
B <- matrix(sample.int(100, size = 50*50, replace = TRUE), nrow = 50, ncol = 50)
C <- matrix(sample.int(100, size = 50*50, replace = TRUE), nrow = 50, ncol = 50)
Obj1 <- vegdist(decostand(A,"standardize",MARGIN=2), method="euclidean")
Obj2 <- vegdist(decostand(B,"standardize",MARGIN=2), method="euclidean")
Obj3 <- vegdist(decostand(C,"standardize",MARGIN=2), method="euclidean")
names1 <- ls(pattern="Obj")
Cmb1 <- combn(names1, 2)
lapply(split(Cmb1, col(Cmb1)), function(x) unlist(mantel(get(x[1]), get(x[2]))[3:4]))
This results in a list of results, for example:
$`1`
statistic signif
0.03006202 0.4070000
There are two questions:
Can i write the two names of the compared objects into the line with "$"? With
split(Cmb1, col(Cmb1)
the names can be obtained.
Thank you for taking your time.
Upvotes: 0
Views: 1986
Reputation: 174778
Is this what you want...?
(using tmp
from
tmp <- sapply(split(Cmb1, col(Cmb1)),
function(x) unlist(mantel(get(x[1]), get(x[2]))[3:4]))
and noting that I made this an sapply()
call so it was easier to extract the statistic
data more easily.)
## zero matrix to fill in - change 0 to be what you want on diagonal
mstat <- matrix(0, ncol = 3, nrow = 3)
## directly fill lower triangle of matrix
mstat[lower.tri(mstat)] <- tmp[1, , drop = TRUE]
## need to transpose
tmstat <- t(mstat)
## then fill in lower triangle again, to get correct order
tmstat[lower.tri(tmstat)] <- tmp[1, , drop = TRUE]
## transpose back
mstat <- t(tmstat)
## add on identifiers
colnames(mstat) <- rownames(mstat) <- names1
> mstat
Obj1 Obj2 Obj3
Obj1 0.00000000 -0.04570113 0.03407708
Obj2 -0.04570113 0.00000000 0.04781475
Obj3 0.03407708 0.04781475 0.00000000
Upvotes: 2