Reputation: 63
Hi all,
I have some code generating a dynamically filled QMenu depending on some data (I will call it thisMenu). The QMenu thisMenu is created, taking some "main" QWidget as parent and is added to a QMenuBar within this QWidget (menuBar.addMenu(&thisMenu). Latter on, I want the user to be able of accessing thisMenu from a context menu (the user right click on some portion of the QWidget, which pops a QMenu (called contextMenu) with some actions, and the previous QMenu as a sub-menu).
If I reuse the QMenu that I first created with contextMenu.addMenu(&thisMenu) I find out that, even if contextMenu pops at the right global position, thisMenu is always translated to some other position and appearing sometimes above, sometimes under contextMenu.
I can test that this is linked to the parenting chain : thisMenu is not a child of contextMenu, if I create it a child of contextMenu, everything is fine. Is there a way of cleanly handling this case without recreating a QMenu similar to thisMenu, or changing the parent of thisMenu; i.e. reusing thisMenu in both QMenuBar and in some context menu/QMenu? In other what is the proper way of handling parenting chain for QMenu and sharing QMenu?
Thank you,
Upvotes: 3
Views: 1720
Reputation: 63
Following JKSH's answer, I decided to use a function to duplicate QMenu, without duplicating the QAction in it (they are not inheriting QWidget), hence conserving all established connections :
void duplicateMenu(QMenu* dst, QMenu& origin)
{
QMenu* sub = dst->addMenu(origin.title());
QList<QAction*> actions=origin.actions();
for(QList<QAction*>::iterator it=actions.begin(); it!=actions.end(); it++)
{
QMenu* itMenu = (*it)->menu();
if(itMenu!=NULL)
duplicateMenu(sub, *itMenu);
else
sub->addAction(*it);
}
}
Upvotes: 3
Reputation: 2718
In other what is the proper way of handling parenting chain for QMenu and sharing QMenu?
You cannot share a QMenu across multiple places -- each QMenu can only exist in one place at a time. You should create separate QMenus: One for your menu bar and one for your context menu.
A simple way is to put your menu-generating code in a for-loop, to create multiple identical menus.
May I ask why you want to reuse your QMenu?
I can test that this is linked to the parenting chain : thisMenu is not a child of contextMenu
Yes, that is described in the documentation. When you add one QMenu to another, the parent doesn't change: http://qt-project.org/doc/qt-5/QMenu.html#addMenu
if I create it a child of contextMenu, everything is fine.
The position of a widget is always painted in a position relative to its parent. (Remember: A QMenu is a QWidget)
Upvotes: 4