CODEWITHSUNDEEP
pythonregex
HugeX
HugeX

Reputation: 13

How can i get a dictionary use re.match() and re.groupdict() with a complex regex?

I kind of wish select the domain name from string and put it into a dictionary. So i use re.match() and re.groupdict() on this string:

Location: hk USER: Will Lee PASS: 1234 INFO: www.hotmail.com

The code is

re.match(r"(?P<Domain>\.([a-zA-Z0-9]+?)\.(?=com))",str).groupdict()

This should make a dictionary which key is "Domain" and value is "hotmail", but somehow it returned:

AttributeError: 'NoneType' object has no attribute 'groupdict'

How can i fix this?

Upvotes: 1

Views: 4388

Answers (2)

SYA-KE
SYA-KE

Reputation: 58

you should use re.match with (?P<..dict key...>) and groupdict(). code:

import re
s="Location: hk USER: Will Lee PASS: 1234 INFO: www.hotmail.com"
yourDict = re.match(r"^Location: (?P<Location>\w+?) USER: (?P<User>.+?(?= PASS: .+? INFO: .+$)) PASS: (?P<Pass>.+?(?= INFO: .+$)) INFO: (?P<Doman>.+$)",s).groupdict()

=> {'User': 'Will Lee', 'Doman': 'www.hotmail.com', 'Location': 'hk', 'Pass': '1234'}

Upvotes: 1

Avinash Raj
Avinash Raj

Reputation: 174816

Use re.search instead of re.match because match tries to find the text from the start. And also you need to give the dot inside the lookahead which asserts capture one or more alphanumeric characters followed by the string .com

>>> re.search(r'(?P<Domain>[a-zA-Z0-9]+)(?=\.com)', s).groupdict()
{'Domain': 'hotmail'}

Upvotes: 3

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