Reputation: 2545
How do I grep the line that followes the @ symbol?
I though this should work: grep -A @ file
@SRR797059.1 HWIEAS269_0001:5:1:1049:4995 length=38
CGAGCTCCGGCTCGGAGGACCATACTATCGTATGCNGN
+SRR797059.1 HWIEAS269_0001:5:1:1049:4995 length=38
bbbbbbbbbbbbbb^bb]_^aR_]_b_b[_BBBBBBBB
@SRR797059.2 HWIEAS269_0001:5:1:1057:20746 length=38
GGATCTGTAAACATCCTCGACTGGAAGCTTACTATCGT
output
CGAGCTCCGGCTCGGAGGACCATACTATCGTATGCNGN
GGATCTGTAAACATCCTCGACTGGAAGCTTACTATCGT
Upvotes: 1
Views: 32
Reputation: 77155
-A
option needs a number after it which would suggest the number of lines you need to print.
From the man
page:
> -A num, --after-context=num
> Print num lines of trailing context after each match.
So you should try:
$ grep -A 1 '@' file
@SRR797059.1 HWIEAS269_0001:5:1:1049:4995 length=38
CGAGCTCCGGCTCGGAGGACCATACTATCGTATGCNGN
--
@SRR797059.2 HWIEAS269_0001:5:1:1057:20746 length=38
GGATCTGTAAACATCCTCGACTGGAAGCTTACTATCGT
$ awk 'p;{p=(/@/?1:0)}' file
CGAGCTCCGGCTCGGAGGACCATACTATCGTATGCNGN
GGATCTGTAAACATCCTCGACTGGAAGCTTACTATCGT
Set the flag for the line that contains @
. Print the next line and disable it.
Upvotes: 1