CODEWITHSUNDEEP
shellsh
user1931682
user1931682

Reputation:

shell script interpreter not identifying the path

I can successfully run the following command in the shell.

export ANT_HOME=/users/user1/workspace/apache-ant-1.7.0

But when I am adding the same line in a shell script, I am getting the following error.

`/users/user1/workspace/apache-ant-1.7.0': not a valid identifier

The shell interpreter is taking -1.7.0 in the path as a arithmetic operation.

How can I fix this ?

EDIT : the shell script which I am trying to run is here.

#!/bin/sh

settingsForANT()
{

export ANT_HOME=/users/user1/workspace/apache-ant-1.7.0
export PATH=${PATH}:${ANT_HOME}/bin

echo $ANT_HOME
echo $PATH

}

settingsForANT

Upvotes: 0

Views: 79

Answers (1)

paxdiablo
paxdiablo

Reputation: 882136

Most likely you either have a $ before the ANT_HOME or a space after the =, probably the latter.

It's complaining about your path being an invalid identifier, meaning it's on the left hand of an assignment, not the right.

If that turns out to be not the case, check the shell you're running the script as. Some do not allow combined set/export and you may need:

ANT_HOME=whatever; export ANT_HOME

Upvotes: 3

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