CODEWITHSUNDEEP
bashfindsubdirectory
Lukas Oppermann
Lukas Oppermann

Reputation: 2938

Bash find folder in least deep subfolder

I have this script for easy moving into folders. My problem is, that if I search for tests but this folder is within my current folder and a subfolder, if the subfolder is searched first, it moves into the tests in the subfolder. But it should always move into the "lowest" match from the subfolder structure. Any ideas?

function f {
  if [[ -d $(find . -name $1 -type d) ]]; then
    cd $(find . -name $1 -type d)
  else
    cd $(find ~ -name $1 -type d)
  fi
}

Upvotes: 0

Views: 263

Answers (2)

Reinstate Monica Please
Reinstate Monica Please

Reputation: 11593

Your question is a bit unclear to me. Are just looking for something like

cd "$(find . -depth -type d -name "$1" -print -quit)"

Which will traverse the directory in dfs order and cd into the first matching $1 it finds.

Upvotes: 0

Fazlin
Fazlin

Reputation: 2337

Try this script:

cd $(for each in `find . -name $1 -type d`
do
   cnt=`echo $each | sed 's:[^/]::g' | awk '{print length}'`
   echo "$cnt $each"
done | sort -g | awk '{print $2}' | head -1)


  • find inside for loop finds all directories with name $1
  • cnt variable counts the no. of "/" in the paths.
  • sort -g sorts the output based on cnt variable.
  • head -1 returns the first item in the sorted list which would be the "lowest" match.

Upvotes: 1

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