CODEWITHSUNDEEP
xsltforeach
Mark Steggles
Mark Steggles

Reputation: 5573

xsl for each number + 1

In a for-each Im using to send 1,2,3,4 for each loop. I would like the count to start at 2 instead of 1. Is that possible?

<xsl:for-each select="BidFeeList/BidFee">
    <xsl:call-template name="chargeField">
        <xsl:with-param name="fieldIndex"><xsl:number/></xsl:with-param>
    </xsl:call-template>
</xsl:for-each>

So the for each would call chargeField template with 2 and then 3,4,5... etc

Upvotes: 0

Views: 136

Answers (1)

Burkart
Burkart

Reputation: 464

If I understand you correctly, you have n BidFeeList/BidFee items and you want to call the chargeField template n times with the parameter fieldIndex set to 2, 3, ..., n+1. This can be achieved with the following XSLT fragment:

<xsl:for-each select="BidFeeList/BidFee">
    <xsl:call-template name="chargeField">
        <xsl:with-param name="fieldIndex" select="position() + 1"/>
    </xsl:call-template>
</xsl:for-each>

Explanation: The XPath function position() returns the context position which in XSLT terminology is the one-based index of the current node in the current node list. In an xsl:for-each the current node list is set to the list of processed nodes and the current node is set to the currently processed node. Thus, position() itself yields 1, 2, ..., n. The + 1 takes care of counting from 2 to n+1 instead.

Upvotes: 1

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