CODEWITHSUNDEEP
lua
user4084132
user4084132

Reputation: 23

Lua, seial number replacement

Part of my code is like this: 

Load_name:addLoad({'incrementalnodalload',        7,           1,    1, 2, 3, 4, 5, 6, 7, 8, 9, 10})

the last part (I mean 1,2,...,10) can be extended as much as required (for example 1,2,...,1000).

Thus I want to replace this part with something like this:

Load_name:addLoad({'incrementalnodalload',        7,           1,    inc_number})

inc_number = 1:1000

However, it does not work!

Any suggestion is highly appreciated!

Upvotes: 1

Views: 44

Answers (1)

Paul Kulchenko
Paul Kulchenko

Reputation: 26774

Here is inc_number function that accepts two parameters and does what you need in this context:

function inc_number(f,t)
  if f > t then return else return f,inc_number(f+1,t) end
end
Load_name:addLoad({'incrementalnodalload', 7, 1, inc_number(1,100)})

Note that it only works when the result of inc_number call is the last parameter in the list of parameters. Example:

print(table.concat({inc_number(1,10)}, ","))
-- prints: 1,2,3,4,5,6,7,8,9,10

Upvotes: 2

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