CODEWITHSUNDEEP
iosobjective-ciphonexcodemacos
Andy
Andy

Reputation: 2601

iPhone 5c Provisioning on Xcode 6 Beta 6

I have just recently registered into Apple developer program.
I have two Xcode environment -
(1) Xcode version 5.1.1
(2) Xcode Version 6.0 (6A279r) or Xcode 6.0 - Beta 6

I am trying to provision my Apple iPhone 5c ( running iOS 7.1) for development purpose, hence I followed the following steps:
(1) Connected the iPhone 5c to USB port of my MacBook Pro Retina Laptop ( OS X 10.9.4)
(2) Opened Xcode 6.0 - Beta 6 and then selected Windows -> Devices menu

I can see that Xcode 6.0-Beta 6 is detecting my iPhone 5c, however I do not see a "Use for Development" option.
So I decided to try it on Xcode 5.1.1 version.

(3) launched Xcode 5.1.1
(4) Opened Windows->Organizer - Devices Tab

I could see that Xcode 5.1.1 is providing me option to provision my Apple iPhone 5c for development purpose.

So why is it that Xcode 6.0 ( Beta 6) is not giving me the option to provision my iPhone 5c for development ?
Is it because it need iOS 8 installed on iPhone 5c ?
Or do I need to do the manual provisioning for Xcode 6.0 - beta 6 ?

Upvotes: 0

Views: 187

Answers (1)

TyloBedo
TyloBedo

Reputation: 495

I believe the "use for development button" simply registers the devices UUID with your apple developer account. From my quick testing in xcode 6 there is no longer a button to hit to do this and instead if you try running an app on a connected phone that doesn't have a UUID registered with your account it will spit you through a few dialog boxes and register it.

Upvotes: 1

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