CODEWITHSUNDEEP
php
callmexshadow
callmexshadow

Reputation: 51

PHP converting (integer) returns to strings

This is something weird that started happening recently.

function someFunction() {
    return 0;
}
if (someFunction() == 0)
    runCode();
elseif (someFunction() == '0')
    runOtherCode();

In this situation runCode() will not be called but instead runOtherCode() will be called. Any reason why this is happening?

Edit: Using === fixed this error in some situations. However the other time this issue was present was when returning integer results from a database. For some reason the integers where being converted into strings but adding (int) to the data before returning the data fixed that error.

Upvotes: 0

Views: 38

Answers (1)

Evadecaptcha
Evadecaptcha

Reputation: 1441

You need to use strict comparison to prevent type coercion. Basically like this:

if(someFunction() === 0) 
elseif(someFunction() === '0')

3 equal signs instead of two invokes a strict comparison and is the only way to differentiate between string and integer comparison.

Edit: This is also relevant in other cases, so always consider it.

Upvotes: 1

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