CODEWITHSUNDEEP
carraysstringcharprogram-entry-point
aNobody
aNobody

Reputation: 117

Reading string character by character in C

So I have a string passed into main function: int main(int argc, char* argv[])

I understand argc (which is 2 in this case), but don't understand how I can read argv[] character by character? When I print argv[0] shouldn't that print the first character in the array of characters for that string?

Thanks

Upvotes: 2

Views: 34046

Answers (2)

ani627
ani627

Reputation: 6057

One more example: 

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main (int argc, char *argv[])
{
    if(argc != 2)
    {
        //argv[0] is name of executable
        printf("Usage: %s argument\n", argv[0]);
        exit(1);
    }
    else
    {
        int i;
        int length = strlen(argv[1]);
        for(i=0;i<length;i++)
        {
            printf("%c",argv[1][i]);
        }
        printf("\n");
        return 0;
    }
}

Upvotes: 0

BLUEPIXY
BLUEPIXY

Reputation: 40145

sample 

#include <stdio.h> 

int main(int argc, char *argv[]){
    int i,j;
    for(i=0; i<argc; ++i){
        for(j=0; argv[i][j] != '\0'; ++j){
            printf("(%c)", argv[i][j]);
        }
        printf("\n");
    }
    return 0;
}

Upvotes: 7

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