CODEWITHSUNDEEP
c++arraysstring
user3600424
user3600424

Reputation: 55

how to create a new array of strings

I don't understand the way this is working. Im tring to create an array of strings from a list of strings. I count the number of strings in the list and then want to create an array of these strings. I was doing some testing and came up with this code:

string *newOrder;

int numNodes;

numNodes = alphaTree.numNodes();

newOrder = new string [numNodes];

newOrder[0] = "This is";
newOrder[1] = "a test";
newOrder[2] = "To see";
newOrder[3] = "If this";
newOrder[4] = "will work";

The results are that newOrder acts like it is a single string array having the vaule "This is". What am I doing wrong?

Upvotes: 0

Views: 104

Answers (2)

o11c
o11c

Reputation: 16036

using std::string;
using std::vector;

// from an initializer_list
vector<string> newOrder1 = {
    "This is",
    "a test",
    "To see",
    "If this",
    "will work",
};

// as a sequence of appends
// often used in a loop if an iterator is not applicable
vector<string> newOrder2;
newOrder2.push_back("This is");
newOrder2.push_back("a test");
newOrder2.push_back("To see");
newOrder2.push_back("If this");
newOrder2.push_back("will work");

// from an iterator-pair over any standards-compliant container
vector<string> newOrder3(alphaTree.begin(), alphaTree.end());

Upvotes: 0

Dr. Debasish Jana
Dr. Debasish Jana

Reputation: 7118

Check if numNodes = alphaTree.numNodes(); is returning desired size.

The following is a correct piece of code, allocates for 5 strings, and assigns.

newOrder = new string [5];
newOrder[0] = "This is";
newOrder[1] = "a test";
newOrder[2] = "To see";
newOrder[3] = "If this";
newOrder[4] = "will work";

If you execute the following statement:

cout << newOrder[2] << endl;

This will print: To see

Upvotes: 1

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