CODEWITHSUNDEEP
pythonregex
Amit
Amit

Reputation: 79

Regex/Python noob needs assistence

I'm trying to pull a specific recurring item from emails using regex and python, the pattern is always:

OS - TYPE - VER - en - he_IL - 1.1.2 - U: username - hash

i was trying to do it with the following condition:

if re.search('U: \s*( - )', message_body)

hoping to get "username" out, unfortunately it didn't give out anything.

also, trying if re.search('U: \w*())', message_body) gave me response that was too broad and included the actual "U: " with the username.

i would love to get some pointers that does not include link to the manual.

Upvotes: 2

Views: 56

Answers (3)

Padraic Cunningham
Padraic Cunningham

Reputation: 180540

You can use split:

s = "OS - TYPE - VER - en - he_IL - 1.1.2 - U: username - hash"
print (s.split("U: ")[1].split()[0])
username

Or using re:

import re
(re.findall(" U:\s+(\w+)",s)[0])
username

re is considerably slower:

In [20]: timeit (re.findall(" U:\s+(\w+)",s)[0])
100000 loops, best of 3: 2.5 µs per loop

In [21]: timeit (s.split("U: ")[1].split()[0])

1000000 loops, best of 3: 764 ns per loop

Upvotes: 1

vks
vks

Reputation: 67988

U:\s*(\S+)

Try this.Use print re.search(r"U:\s*(\S+)",x).group(1) to get username.

Here x is your string.

See demo.

http://regex101.com/r/lS5tT3/73

Upvotes: 1

isedev
isedev

Reputation: 19641

Use a capture group with an actual expression:

match = re.search('U:\s*(\S+)')
if match: username = match.group(1)

match = re.search('U:\s*(\S+ - \S+)')
if match: username_and_hash = match.group(1)

match = re.search('U:\s*(\S+) - (\S+)')
if match:
    username = match.group(1)
    userhash = match.group(2)

Upvotes: 1

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