CODEWITHSUNDEEP
scala
matanox
matanox

Reputation: 13686

Why does scala convert Seq to List?

> val a:Seq[Integer] = Seq(3,4)
a: Seq[Integer] = List(3, 4)

If Seq is only a trait, why does the compiler / REPL accept it, and does it behave like that for many other traits or even abstract classes?

Upvotes: 9

Views: 9483

Answers (2)

tuxdna
tuxdna

Reputation: 8487

The default implementation for Seq is a List as mentioned in scaladoc here:

Seq Object

Which says

This object provides a set of operations to create Seq values. The current default implementation of a Seq is a List.

When calling Seq(3,4) you actually invoke Seq.apply(3,4) which builds a sequence of two elements as a List underneath.

Upvotes: 7

soulcheck
soulcheck

Reputation: 36767

It doesn't convert anything.

Seq is a trait, you can't really instantiate it, only mix it in to some class.

Since apply method of the Seq companion object has to return some concrete class instance (that mixes in Seq trait), it returns a List which seems to be a reasonable default.

One situation this can be useful in, is when you need some Seq instance, but don't care about implementation and don't have time to look at the type hierarchy to find a suitable class implementing Seq. Seq(3,4) is guaranteed to give you something that obeys the Seq contract.

Upvotes: 9

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