CODEWITHSUNDEEP
phparrays
UBEX
UBEX

Reputation: 122

How to test if value is in array PHP (key search)

This is my array in PHP:

$arr['key1']='value1';
$arr['key2']='value2';
$arr['key3']='value3';
$arr['key4']='value4';
$arr['key5']='value5';
$arr['key6']='value6';

I would like to test if a key is in the array. Is this function the correct way to proceed?

function isKeyInArray($key, $arr) {
   if(isset($arr[$key]))
      return true;
   else
      return false;
}

What I expect is that:

isKeyInArray('key3', $arr) // return true
isKeyInArray('key9', $arr) // return false

Many thanks in advance.

Upvotes: 0

Views: 186

Answers (4)

Shemil R
Shemil R

Reputation: 49

Use php function array_key_exists('key3', $a);

First google your need and only after that you can use your own function. This will save lots of your time.

Upvotes: 0

olvlvl
olvlvl

Reputation: 2474

Using isset() is good if you consider that null is not a suitable value. Also isset is faster than array_key_exists.

$a = [ 'one' => 1, 'two' => null ];
isset($a['one']); // true
isset($a['two']); // false
array_key_exists('two', $a); // true

Upvotes: 2

Manwal
Manwal

Reputation: 23836

Use array_key_exists

if(array_key_exists('key6',$arr))
   echo "present";
else
   echo "not present";

Upvotes: 4

TeeDeJee
TeeDeJee

Reputation: 3741

You can use array_key_exists.

$a=array("Volvo"=>"XC90","BMW"=>"X5");
if (array_key_exists("Volvo",$a))
  {
  echo "Key exists!";
  }
else
  {
  echo "Key does not exist!";
  }

See http://php.net/manual/en/function.array-key-exists.php

Upvotes: 6

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