Reputation: 2045
I would like to cut left part of text when I will find character '#' :
Text:
1) 12341#123
2) 123#1
Correct Result:
1) 123
2) 1
Do you know how?
I try use this but does not work:
LEFT(A.Vat,CHARINDEX('#',A.Vat)-1)
Upvotes: 0
Views: 14922
Reputation: 175766
Assuming always only 1 #
:
SELECT SUBSTRING(f, CHARINDEX('#', f) + 1, LEN(f))
For more than 1 #
SELECT RIGHT(f, CHARINDEX('#', REVERSE(f)) - 1)
Upvotes: 1
Reputation: 18411
General rule:
select RIGHT(fieldName,len(fieldName) - patindex('%#%',fieldName))
Examples:
select RIGHT('12341#123',len('12341#123') - patindex('%#%','12341#123'))
select RIGHT('123#1',len('123#1') - patindex('%#%','123#1'))
Upvotes: 2