Reputation: 1307
I created a test using grep
but it does not work in sed
.
grep -P '(?<=foo)bar' file.txt
This works correctly by returning bar
.
sed 's/(?<=foo)bar/test/g' file.txt
I was expecting footest
as output, but it did not work.
Upvotes: 52
Views: 25728
Reputation: 510
Powershell's -replace
supports lookaheads:
(Get-Content -Raw file.tsv) -replace '(?<=\t)\\N(?=\t)','' | Set-Content file.tsv
It removes \N
from empty tsv cells for 900mb file in 7s. But beware of possibly converted line breaks.
Upvotes: 0
Reputation: 131
sed doesn't support lookarounds but choose (I'm the author) does. It uses PCRE2 syntax.
For example:
$ echo "hello bar foobar" | choose -r --sed '(?<=foo)bar' --replace test
hello bar footest
It's speed is comparable to sed.
Upvotes: 1
Reputation: 89629
Note that most of the time you can avoid a lookbehind (or a lookahead) using a capture group and a backreference in the replacement string:
sed 's/\(foo\)bar/\1test/g' file.txt
Simulating a negative lookbehind is more subtile and needs several substitutions to protect the substring you want to avoid. Example for (?<!foo)bar
:
sed 's/#/##/g;s/foobar/foob#ar/g;s/bar/test/g;s/foob#ar/foobar/g;s/##/#/g' file.txt
#
=> ##
).foobar
here, => foob#ar
or ba
=> b#a
).foob#ar
with foobar
(or b#a
with ba
).##
with #
.Obviously, you can also describe all that isn't foo
before bar
in a capture group:
sed -E 's/(^.{0,2}|[^f]..|[^o].?)bar/\1test/g' file.txt
But it will quickly become tedious with more characters.
Upvotes: 53