CODEWITHSUNDEEP
python
city
city

Reputation: 2154

how to convert an array to a dict in python

Now, I wanna convert an array to a dict like this:

dict = {'item0': arr[0], 'item1': arr[1], 'item2': arr[2]...}

How to solve this problem elegantly in python?

Upvotes: 3

Views: 5493

Answers (7)

sudar
sudar

Reputation: 151

Using map, this could be solved as:

a = [1, 2, 3]
d = list(map(lambda x: {f"item{x[0]}":x[1]}, enumerate(a)))

The result is:

[{'item0': 1}, {'item1': 2}, {'item2': 3}]

Upvotes: 0

salmanwahed
salmanwahed

Reputation: 9647

You can also use the dict() to construct your dictionary. 

d = dict(('item{}'.format(i), arr[i]) for i in xrange(len(arr)))

Upvotes: 2

Cameron Lee
Cameron Lee

Reputation: 1103

Use dictionary comprehension: Python Dictionary Comprehension

So it'll look something like:

d = {"item%s" % index: value for (index, value) in enumerate(arr)}

Note the use of enumerate to give the index of each value in the list.

Upvotes: 1

ragingSloth
ragingSloth

Reputation: 1104

you could use a dictionary comprehension eg. 

>>> x = [1,2,3]
>>> {'item'+str(i):v for i, v in enumerate(x)}
>>> {'item2': 3, 'item0': 1, 'item1': 2}

Upvotes: 1

eri0o
eri0o

Reputation: 2450

simpleArray = [ 2, 54, 32 ]
simpleDict = dict()
for index,item in enumerate(simpleArray):
    simpleDict["item{0}".format(index)] = item

print(simpleDict)

Ok, first line Is the input, second line is an empty dictionary. We will fill it on the fly.

Now we need to iterate, but normal iteration as in C is considered non Pythonic. Enumerate will give the index and the item we need from the array. See this: Accessing the index in Python 'for' loops.

So in each iteration we will be getting an item from array and inserting in the dictionary with a key from the string in brackets. I'm using format since use of % is discouraged. See here: Python string formatting: % vs. .format.

At last we will print. Used print as function for more compatibility.

Upvotes: 1

DSM
DSM

Reputation: 353169

You could use enumerate and a dictionary comprehension:

>>> arr = ["aa", "bb", "cc"]
>>> {'item{}'.format(i): x for i,x in enumerate(arr)}
{'item2': 'cc', 'item0': 'aa', 'item1': 'bb'}

Upvotes: 13

icedtrees
icedtrees

Reputation: 6466

Suppose we have a list of ints:

We can use a dict comprehension

>>> l = [3, 2, 4, 5, 7, 9, 0, 9]
>>> d = {"item" + str(k): l[k] for k in range(len(l))}
>>> d
{'item5': 9, 'item4': 7, 'item7': 9, 'item6': 0, 'item1': 2, 'item0': 3, 'item3': 5, 'item2': 4}

Upvotes: 2

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