CODEWITHSUNDEEP
phpjsonparsinglaravel
sarovarc
sarovarc

Reputation: 407

Reading JSON data in PHP

I have a JSON object like below, which is stored in a variable called $product.

{"id":30}

When I try to access the stored value though, I get the following error:

Trying to get property of non-object

Here is what I am doing:

echo $product->id;

Alright folks, sorry for the wild goose chase. Apparently $products was an array and not a JSON data, which is really odd because print_r($products) and echo $products gave different results.

The results can be viewed here:

results

I am using Laravel, and usually laravel returns a nice JSON object from an SQL query, I must have changed something somewhere, which is why this happened. Thanks.

Upvotes: 1

Views: 95

Answers (4)

Mathias Jørgensen
Mathias Jørgensen

Reputation: 64

The first examples are working for me, make sure you PHP is supporting the json_decode() function. Or you could try this:

$product = '{"id":30}';
$t = json_decode($product, true);
echo $t["id"];

Passing the true value converts it to an array instead.

Upvotes: 0

Junyoung LEE
Junyoung LEE

Reputation: 107

Trying below sample :

<?php
$product = '{"id": 30}';

$obj = json_decode(json_encode($product));  // or json_decode(json_encode($product), true);
echo $obj->{'id'};  // or echo $obj->id
?>

Upvotes: 0

Adam Sinclair
Adam Sinclair

Reputation: 1649

You could use json_decode to your object.

Takes a JSON encoded string and converts it into a PHP variable.

usage:

print_r(json_decode($obj, true));
var_dump(json_decode($obj));

Upvotes: 0

Bhumi Shah
Bhumi Shah

Reputation: 9474

Try following json_decode function

$product = '{"id":30}';
$t = json_decode($product);
echo $t->id;exit;

Upvotes: 1

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